Measuring resistance of thermistor in potential dividers

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SUMMARY

The discussion focuses on the advantages of using a potential divider circuit for measuring the resistance of a thermistor compared to a simple ohmmeter setup. Key points include the importance of measuring current flow through the thermistor and how heat generated from current can affect resistance readings. The potential divider circuit helps mitigate errors caused by self-heating of the thermistor, leading to more accurate measurements. Participants emphasize the significance of understanding electrical principles such as Ohm's Law and power equations in this context.

PREREQUISITES
  • Understanding of potential divider circuits
  • Familiarity with thermistor characteristics
  • Knowledge of Ohm's Law and power equations (P = IE, I²R, V²/R)
  • Experience with using voltmeters for voltage measurements
NEXT STEPS
  • Research the design and application of potential divider circuits in sensor measurements
  • Learn about thermistor types and their temperature-resistance characteristics
  • Study the effects of self-heating on thermistor accuracy
  • Explore advanced measurement techniques for improving thermistor readings
USEFUL FOR

Electronics students, engineers working with temperature sensors, and anyone involved in circuit design and measurement accuracy in thermistor applications.

lefty989
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Hi there, first off I hope this is ok to post here. Quite a simple question.
I have done an experiment simply to work out the resistance of a thermistor at different temperatures, I did a prelim with a simple circuit of just ohm meter + thermistor. Then I did the main one with a potential divider circuit.

1. What is the advantage of using a potential divider circuit over a simple one to measure resistance of a thermistor? (Read above)

Thanks for any replies. I'm a bit unsure as to why it would be better. :-/
 
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lefty989 said:
Hi there, first off I hope this is ok to post here. Quite a simple question.
I have done an experiment simply to work out the resistance of a thermistor at different temperatures, I did a prelim with a simple circuit of just ohm meter + thermistor. Then I did the main one with a potential divider circuit.

1. What is the advantage of using a potential divider circuit over a simple one to measure resistance of a thermistor? (Read above)

Thanks for any replies. I'm a bit unsure as to why it would be better. :-/

What were the currents flowing through the thermistor in two different circuits?
You can calculate this by getting a voltmeter and measuring the voltage output of your ohmmeter.

My voltmeter measures 3.051 vdc from my ohmmeter on the 2k ohm scale.
 
OmCheeto said:
What were the currents flowing through the thermistor in two different circuits?
You can calculate this by getting a voltmeter and measuring the voltage output of your ohmmeter.

My voltmeter measures 3.051 vdc from my ohmmeter on the 2k ohm scale.

Why is this necessary? I just need to know what makes this circuit a better way to do it.

But the current at say 20degrees was about 0.4 set at 20mA for potential divider. I didn't check the current for the other circuit. just had a resistance meter and thermistor.
 
lefty989 said:
Why is this necessary?
Because it points you to the answer.
I just need to know what makes this circuit a better way to do it.

But the current at say 20degrees was about 0.4 set at 20mA for potential divider. I didn't check the current for the other circuit. just had a resistance meter and thermistor.

You need to know how much current is flowing through the thermistor in each of the circuits, and how that current affects your readings. Are you familiar with the equations:
P = IE = I2R = V2/R

And how does P manifest itself in a purely resistive circuit?

And how does that affect R of the thermistor?

And how does that affect your measurements?

If you answer all of my questions, you will have the answer to your question.
 
Right... Thanks for the help..

Im not really understanding what you mean by the first question.
And how does P manifest itself in a purely resistive circuit?
Yes I do know the equations.
 
lefty989 said:
Right... Thanks for the help..

Im not really understanding what you mean by the first question.

OmCheeto said:
And how does P manifest itself in a purely resistive circuit?

(Excuse me for jumping in.)

I think OmCheeto is asking, what happens to the electrical energy when current flows through a resistor? (Hint: it gets transformed from electrical energy into ____ energy.)
 
Redbelly98 said:
(Excuse me for jumping in.)

I think OmCheeto is asking, what happens to the electrical energy when current flows through a resistor? (Hint: it gets transformed from electrical energy into ____ energy.)

Ahh ok. Hope I am right in saying heat energy? So a guess, does this mean the heat will affect the resistance output from the thermistor? That makes sense, so you use a potential divider circuit to eliminate that problem?
I am not quite sure why... (Is it something to do with the other resistor in series?)
 

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