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I'm pretty sure I did this one wrong, =( please help clarify?

8. At the Calgary Stampede, you can win a prize if the bell rings when you strike a wooden block with a 10.0-kg hammer. The block is at one end of a lever. The other end of the lever drives a 2.0-kg metal bar up a slide to ring the bell 9.0 m above. What is the minimum speed the hammer must be swung to make the bar hit the bell?

Assuming there are no energy losses, the energy required to be transmitted to the 2.0-kg bar can be calculated and used as the kinetic energy required for the hammer.

Ek = 1/2mv^2

Ep = mgh

Em = Ep + Ek

v = √[(2•Ek)/m]

m1 = 10.0kg

m2 = 2.0kg

mt = m2 + m1 = 12.0kg

D = 9.0m

Ep = mgh

= (2.0kg)(9.0m)(9.81m/s^2)

= 176.58 J

Hammer:

h = 0m

v = √[(2•Ek)/m] + mgh

= √[(2•176.58J)/10.0kg] + (10.0kg)(9.81m/s^2)

= 104.042726646919

v = 1.0x10^2 m/s

The hammer should have a velocity of 1.0x10^2 J when it hits the wooden block, causing 1.77x10^2 J of energy on the 2.0kg block.

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# Homework Help: Mechanical Energy vs Potential Energy & Kinetic Energy

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