# Mechanical resistence with vacuum

• davidgruty
In summary, the conversation is about calculating the number and dimensions of "plugs" needed to hold two plates (made of aluminium and carbon fibre) together and flat, while taking into account the pressure difference between the vacuum inside the plates and the atmosphere outside. Various suggestions and equations are provided for calculating the stress and buckling strength of the materials involved, as well as the necessary tributary areas. It is also suggested to use consistent units of measurement for accurate calculations. Ultimately, the conversation ends with the acknowledgement that the pressure difference between the inside and outside of the plates is the key factor in determining the dimensions and number of "plugs" needed.
davidgruty
Hello!

I have to calculate some pieces (brown "plugs" and green ring) which hold two plates of 2 mm each. They are made of an insulation material (different the green and the brown one) with known properties.

One plate is made of aluminium and the other of carbon fibre.

Inside the two plates there is vacuum.

The point is I want to hold the two plates keeping them flat (no dent) and calculate the number and dimension of the "plugs" (they have to be placed in a homogeneous way, the paint drawing is not very good...)

Can anyone help me?

The problem I have is the vacuum, I made some calculations with forces but never with vacuum.

Thank you very much.

Regards

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davidgruty said:
Hello!

I have to calculate some pieces (brown "plugs" and green ring) which hold two plates of 2 mm each. They are made of an insulation material (different the green and the brown one) with known properties.

One plate is made of aluminium and the other of carbon fibre.

Inside the two plates there is vacuum.

The point is I want to hold the two plates keeping them flat (no dent) and calculate the number and dimension of the "plugs" (they have to be placed in a homogeneous way, the paint drawing is not very good...)

Can anyone help me?

The problem I have is the vacuum, I made some calculations with forces but never with vacuum.

Thank you very much.

Regards

Well I'm quite certain I do not understand your drawing or question, however, I may be able to offer one piece of advice that may help: Vacuums do not exert a force on anything.

CS

So basically you are saying that you have 14.7 psia acting on the outer surfaces creating a compressive force through the plates to the insulation pieces which appear to be rods?

davidgruty: To perform your stress analysis (finite element analysis), apply an external pressure of p = FSu*(101 325 Pa) to the outer surfaces of your aluminum and carbon fibre circular plates (and also to the outer surface of your black cylinder, if applicable), where FSu = ultimate factor of safety. After you finish this stress analysis, also check the buckling strength of the brown rod having the highest axial load, and check the buckling strength of a longitudinal strip of your green cylinder.

Hello all,

Thank you for your responses.

- stewartcs:

Sorry for my drawing; it's actually very bad. The idea is we have two metal layers separated by some plugs which I have to calculate because between the two layer there is vacuum (0,03 Torr = 0.000580103 psi). And out of the layers there is atmosphere pressure which try to crush the layers (that's why we place the plugs).

- FredGarvin:

Yes. you are right.

Maybe the solution is to subtract the in-pressure from the atmosphere pressure and then since I know the properties of the material I can calculate the surface needed. The problem is the number of plugs and the separation.

- nvn:

I would like to do this "by hand" not using any FEA software.

Thank you all!

davidgruty: If you do not want to use FEA, divide the circular plate into tributary areas for the brown rods and the green cylinder. If the green cylinder is relatively much more flexible than the brown rod, then make the tributary area for the outer brown rods relatively bigger, or even extending to the edge of the circular plate. If the brown rod is relatively much more flexible than the green cylinder, then make the tributary area for the green cylinder relatively bigger. Because your internal pressure is 0.03 torr = 4 Pa (absolute), apply an external pressure of p = FSu*(101 321 Pa) to the outer surface of your aluminum and carbon fibre circular plates, where FSu = ultimate factor of safety. Compute the axial stress on a brown rod, sigma = p*Apr/Ar, where Apr = tributary area for brown rod, and Ar = brown rod cross-sectional area. Ensure sigma/Scur < 100 %, where Scur = brown rod material compressive ultimate strength. (But if the brown rod or green cylinder material has a yield strength, let us know.) Also ensure sigma/sigma_crr < 100 %, where sigma_crr = brown rod buckling strength.

Compute the axial stress on a longitudinal strip (of unit width) of the green cylinder, sigma = p*Apc/Ac, where Apc = tributary area for green cylinder unit width, and Ac = green cylinder cross-sectional area per unit width. Ensure sigma/Scuc < 100 %, where Scuc = green cylinder material compressive ultimate strength. Also ensure sigma/sigma_crc < 100 %, where sigma_crc = green cylinder buckling strength per unit width. If the black cylinder is applying significant pressure to the green cylinder, then the analysis of the green cylinder becomes more complicated than described above.

Use consistent units, N, m, Pa; or N, mm, MPa. If you use N, mm, MPa, apply an external pressure of p = FSu*(0.101 321 MPa) to the outer surface of your aluminum and carbon fibre circular plates.

Also compute the axial contraction (shortening), delta, of the brown rod when the external pressure you apply to the circular plate tributary area is p = 101 321 Pa, ignoring the circular plate deflection; and ensure delta does not exceed the maximum amount of circular plate displacement you want. Likewise, check the axial shortening of the green cylinder per unit width.

nvn,

Thank you very much for your answer.

Sorry for the delay (I had to draw and postpone the calculations)

The most important point was the pressure around the two plates. It's just subtract the external from the internal.

Thank you; you helped to the science go forward!

## 1. What is mechanical resistance with vacuum?

Mechanical resistance with vacuum is a measure of an object's ability to withstand external forces and maintain its structural integrity in a vacuum environment. This resistance is primarily due to the lack of air molecules in a vacuum, which reduces the amount of pressure and friction acting on the object.

## 2. How is mechanical resistance with vacuum measured?

Mechanical resistance with vacuum is typically measured using specialized equipment, such as a vacuum chamber or a vacuum pump. These tools are used to create and maintain a vacuum environment, while various forces are applied to the object to test its resistance. The resulting data is then analyzed to determine the object's mechanical resistance.

## 3. Why is mechanical resistance with vacuum important?

Mechanical resistance with vacuum is important in various fields such as aerospace, material science, and engineering. It allows scientists and engineers to design and test objects that can withstand extreme environments, such as space or high altitudes. Understanding an object's mechanical resistance with vacuum also helps ensure its safety and reliability in these environments.

## 4. How does mechanical resistance with vacuum differ from regular mechanical resistance?

Regular mechanical resistance refers to an object's ability to withstand external forces in a normal atmospheric environment. In contrast, mechanical resistance with vacuum takes into account the unique conditions of a vacuum, where there is no air pressure or friction. This requires a different set of testing methods and considerations.

## 5. Can mechanical resistance with vacuum be improved?

Yes, mechanical resistance with vacuum can be improved through various methods such as selecting materials with high strength-to-weight ratio, using special coatings or surface treatments, and optimizing the design and structure of the object. Additionally, ongoing research and development in this field continue to advance the understanding and improvement of mechanical resistance with vacuum.

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