Mechanics: Inelastic Collisions Questions

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SUMMARY

This discussion focuses on the mechanics of inelastic collisions, specifically addressing the coefficient of restitution and its application. The formula for inelastic collisions involves the velocity of approach equating to the negative product of the coefficient of restitution and the velocity of separation. Participants clarify that the method of adding and subtracting velocities depends on the dimensionality of the collision rather than the type of collision. Additionally, the conservation of momentum is essential for determining the correct directions of velocities post-collision.

PREREQUISITES
  • Understanding of inelastic collisions and their characteristics
  • Familiarity with the coefficient of restitution
  • Knowledge of conservation of momentum principles
  • Basic concepts of kinetic energy in collision scenarios
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  • Study the mathematical derivation of the coefficient of restitution in inelastic collisions
  • Learn about conservation of momentum in one, two, and three-dimensional collisions
  • Explore the differences between elastic and inelastic collisions in detail
  • Investigate the implications of kinetic energy loss during inelastic collisions
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Students of physics, educators teaching mechanics, and anyone interested in understanding the principles of inelastic collisions and their mathematical representations.

Jadenag
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Guys this is my first post on this site. Not sure If this is the correct thread but lmk?
Im having a tough time dealing with inelastic collisions. I am not entirely sure about the coefficient of restitution. I used to study a formula in Physics which was speed of aproach= Speed of separation for elastic collisions. Now in mechanics I am using the same formula but its velocity of approach=(-e)(velocity of separation) I believe. I firstly am having an issue with the directions of the velocities. Previously with elastic collisions Id just add the two in opposite directions and subtract the two in the same direction. Also. This coefficient of restitution. Is it also applicable to the Kinetic Energy before and after the inelastic collision? Is this also a formula: Initial K.E= (-e)(Final K.E) ? Thankyou.
 
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"Adding in opposite directions and subtracting in the same direction" has nothing at all to do with "elastic" collisions. It has to do with whether you are dealing with collisions in one (on a line), two (on a plane), or three (in space) dimensions.

Yes, the total energy after the collision is equal to the total energy before the collision times the "coefficient of restitution". You will also need to use "conservation of momentum" to get directions right.
 

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