Mechanics Newton's 2nd law question

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SUMMARY

The discussion revolves around applying Newton's 2nd Law to a physics problem involving a 200kg load lifted through 50m. The load accelerates uniformly for 20 seconds, maintains a constant speed for 10 seconds, and then decelerates over another 10 seconds. Key equations include F=ma and SUVAT equations, which are essential for determining the maximum speed attained and the tension in the cable during each phase of motion. The solution requires calculating acceleration first before addressing tension in the cable.

PREREQUISITES
  • Understanding of Newton's 2nd Law (F=ma)
  • Familiarity with SUVAT equations for constant acceleration
  • Basic knowledge of kinematics and motion analysis
  • Ability to solve equations involving multiple stages of motion
NEXT STEPS
  • Study the derivation and application of SUVAT equations in detail
  • Learn how to calculate tension in cables under varying loads
  • Explore examples of uniform acceleration and deceleration problems
  • Practice solving multi-stage motion problems in physics
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Students studying physics, particularly those focusing on mechanics and kinematics, as well as educators seeking to enhance their teaching methods in these topics.

pianogirl
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Homework Statement


A load of 200kg is lifted through 50m by a vertical cable. The load accelerates uniformly from rest for 20 seconds, travels at constant speed for 10 seconds then decelerates to rest in a further 10 seconds. Find the maximum speed attained and the tension in the cable at each stage.



Homework Equations


F=ma and maybe some SUVAT ones?



The Attempt at a Solution


I started using F=ma so that for the first stage I got T=200a+1960 but soon after that I got a bit confused.

Help would be really appreciated because I'm stuck!
Thanks!
 
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Hi pianogirl! :smile:

Forget the tension … you need to find the acceleration before you can find the tension. :wink:

Write out the standard constant acceleration equations for the three stages of motion, plus the equation that says the three distances add to 50m.

What do you get? :smile:​
 

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