Mechanics Projectile Questions

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SUMMARY

The discussion focuses on a physics problem involving projectile motion, where a particle is projected horizontally from point A with a position vector of (5i + 30j) m and passes through point B at (17i + 10.4j) m. The speed of projection is calculated to be 6 m/s, and the time taken to travel from A to B is determined to be 2 seconds. Key equations utilized include s = ut + 0.5at² and v = s / t, confirming the calculations for both speed and time.

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thomas49th
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Homework Statement


At time t = 0 a particle is projected horizontally from a point A with position vector (5i + 30j)m. It passes through point B with position vector (17i +10.4j)m. Find:
- Its speed of projection
- Time taken to travel from A to B

Homework Equations



s = ut + 0.5at²

v² = u² + 2as

v = s / t

a = (v - u) / t

v = s / t

The Attempt at a Solution



Well from A to B the i and j components are

12i
-19.6j

i can draw a right angled triangle and use pythagerous's thyrom and calculate that the other side is 12.8 (3.s.f) - is that meters?

Have i gone the right way. I don't know what to do now. Any hints
 
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Ahh i worked out the vertical component and got t = 2

now...
 
then put this into v = s / t

v = 6m/s and t = 2s

yeh :)
 

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