Mechanics question not even that advanced

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Homework Help Overview

The discussion revolves around a mechanics problem involving a block on a frictionless ramp that transitions from a height of 3.91m to a point A where it levels out, and then to point B where it exits at a 45-degree angle. Participants are exploring the forces acting on the block at points A and B, particularly questioning the nature of the normal force and the role of centripetal acceleration.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the forces at play, with some suggesting that the normal force at point A is simply mg, while others express doubt about the simplicity of this conclusion. There is also consideration of the implications of centripetal acceleration at point B and how it relates to the given radius and angle.

Discussion Status

The conversation is ongoing, with some participants expressing confusion about the problem's setup and the assumptions made regarding the radius and the forces involved. There is a mix of interpretations regarding the calculations needed at point B, and a request for a diagram indicates a desire for clarification.

Contextual Notes

Participants note that the problem lacks clarity in its explanation, particularly regarding the relationship between the radius and the forces at point B. There is also mention of the problem's complexity despite its classification as non-advanced physics.

schattenjaeger
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So if you have a block sitting on top of a frictionless slide(it's a ramp, so it goes down like a slide, levels out at the bottom at point A, then curves back up and ends at point B.)the height at the top of the slide is 3.91m, and the mass of the block is 1.62kg, the angle at point B is 45 degrees from the horizontal(err, in case that wasn't clear, at point B the block goes flying off at 45 degrees)and the height of point B is not given

so anyhoo, it wants to know the force exerted on the block by the track at point A(where it levels out) wouldn't that just be mg? That seems too simple though. Same thing at point B but with some trig fiddling to get like cos(45)*mg. I guess it COULD be that simple, there's two more parts to the problem that are giving me LESS problems just because I'm not second guessing myself, but I dunno.

Edit: I guess that doesn't really make sense though. In that case the force is constant, but obviously as you go faster and pull up like that, you're applying a greater force down(and hence the track is pushing up harder)
 
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Well I found the solution online, but I want to call BS! I figured it would involve centripetal acceleration in some way, but it gives me an R and angle, but by the time it reaches point B it's lost that circular motion clearly in the picture, and it's not stated in the problem. Or something, I just suck I guess
 
It really is that simple. At point A, the force exerted is mg, and at point B it would be m*sin(45). And you're right; this isn't exactly advanced Physics. :-p

Edit: I'm confused now. Could you get a diagram of what this situation is supposed to look like?
 
Yah, like I said the problem kinda fudges on its explanation. Later in the problem I need to do calculations at point B using that same R that's given, but in the picture they're clearly not the same distance from the center of the "circle" but whatever
 
http://img152.imageshack.us/my.php?image=untitled3ze.png
exagerated features 'cuz I suck at drawing, especially on comps
A's at the bottom, B's the end point, it makes perfect sense if you assume R is the same length as the line going to B, and then it's fine, but you can't really assume that, can you? Obviously the problem does, I'm just saying. The answer, fyi, is Normal force=mg(1+2h/R)
 

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