I've come across a question which is asking what would happen in a cell with odd diploid number 2n=15 when it undergoes meiosis. Here's my thinking: - 15 chromosomes, so 7*2 homologues + 1 loner? - Hence, after Meiosis I, we'd have 7 chromosomes in one cell, and 8 in the other? - After meiosis II, we'd have 2 cells with 7 chromosomes, and 2 cells with 8? Just wanted to check that this is a plausible answer for this situation? It seems a bit rare, and odd 2n appears to be associated with infertility (e.g. mules). Would appreciate a confirmation of this :) Thanks!