Merry-go-round + sphere tied to rod

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SUMMARY

The discussion focuses on calculating the angular velocity of a sphere suspended from a merry-go-round using principles of physics. The sphere has a mass of 0.160 kg and is positioned at a radius of 0.440 m from the axis of rotation. The equilibrium position is defined by distances a = 0.430 m and b = 0.760 m. Participants emphasize the application of Newton's 2nd law and suggest drawing a free body diagram to identify the forces acting on the sphere, ultimately concluding that torque calculations are unnecessary for this problem.

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Homework Statement



A small 0.160 kg sphere is suspended by a light string from a vertical post mounted at the edge of a merry-go-round of radius R = 0.440 m.
The equilibrium position of the sphere is shown in the figure, with a = 0.430 m and b = 0.760 m. The axis of rotation is indicated by the dashed line. Calculate the angular velocity of the merry-go-round.

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The Attempt at a Solution



This is where I'm getting stuck. I can't figure out where to start. I have an idea that this problem deals with Newton's 2nd law, but I don't know how to apply it this situation.

Would using the torque equation help?: [tex]\tau = F * r * sin\theta[/tex]
 
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Follow standard procedure: Draw a free body diagram of the sphere, showing all the forces acting on it. (Hint: There are only two forces.) Key: What's the acceleration of the sphere? Then apply Newton's 2nd law.

(No need for torques.)
 

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