1. The problem statement, all variables and given/known data a 12 kg meteor experiences an acceleration of 7.2 m/s^2, when faling towards the earth. How high above the Earths surface is the meteor? 2. Relevant equations mass of earth= 5.98x1024 kg radius of earth= 6.36x106 m g=G*MEarth/r2 r=√G*ME/g 3. The attempt at a solution r=√G*ME/g =√(6.67x10-11)(5.98x1024)/(7.2) =7.4x106 m 7.4x106-6.36x106 =1.06 x106 m above the Earths surface, or 1060 km? Does everything look good? Thanks in advance for any help!