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Meteor Accelerating towards the Earth

  1. Dec 18, 2011 #1
    1. The problem statement, all variables and given/known data

    a 12 kg meteor experiences an acceleration of 7.2 m/s^2, when faling towards the earth.

    How high above the Earths surface is the meteor?


    2. Relevant equations
    mass of earth= 5.98x1024 kg
    radius of earth= 6.36x106 m

    g=G*MEarth/r2

    r=√G*ME/g



    3. The attempt at a solution

    r=√G*ME/g
    =√(6.67x10-11)(5.98x1024)/(7.2)
    =7.4x106 m

    7.4x106-6.36x106
    =1.06 x106 m above the Earths surface, or 1060 km?

    Does everything look good? Thanks in advance for any help!
     
  2. jcsd
  3. Dec 18, 2011 #2
    This looks OK.
    Did you realise you did not need the mass of the meteor in the calculation??
     
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