Meteor Accelerating towards the Earth

[HarleyM]

Homework Statement

a 12 kg meteor experiences an acceleration of 7.2 m/s^2, when faling towards the earth.

How high above the Earths surface is the meteor?

Homework Equations

mass of earth= 5.98x10²⁴ kg
radius of earth= 6.36x10⁶ m

g=G*M_Earth/r²

r=√G*M_E/g

The Attempt at a Solution

r=√G*M_E/g
=√(6.67x10^-11)(5.98x10²⁴)/(7.2)
=7.4x10⁶ m

7.4x10⁶-6.36x10⁶
=1.06 x10⁶ m above the Earths surface, or 1060 km?

Does everything look good? Thanks in advance for any help!

 

[technician]

This looks OK.
Did you realize you did not need the mass of the meteor in the calculation??