Meter stick and rock balancing ?

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SUMMARY

A uniform meter stick supported at the 25-cm mark achieves equilibrium when a 1-kg rock is suspended at the 0-cm end. The mass of the meter stick is less than the mass of the rock, as the torque produced by the rock must be balanced by the torque produced by the meter stick's weight acting at its center of mass (50 cm). An extended free body diagram illustrates the forces and torques acting on the system, confirming this conclusion.

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A uniform meter stick supported at the 25-cm mark is in equilibrium when a 1-kg rock is suspended at the 0-cm end. Is the mass of the meter stick greater than, equal to, or less than the mass of the rock? Explain your reasoning.

Thanks in advance for any help!
 
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Can you draw an extended free body diagram for the situation?
 
I see you're fairly new, but you have to show that you tried before you get any help.
 

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