Method of image with Green function

Click For Summary

Homework Help Overview

The discussion revolves around a problem involving a conducting sphere composed of three different shells with varying electric potentials. The original poster seeks guidance on finding the electric potential at a specific point, particularly in the context of the method of images and Green's functions, while expressing confusion about the setup due to the size of the middle shell.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the method of images as a potential approach, with some questioning the original poster's understanding of the problem setup and the implications of the middle shell's size.

Discussion Status

The discussion reflects a mix of attempts to clarify the problem and the original poster's frustration with the responses. While some participants suggest focusing on the method of images, there is no explicit consensus on the next steps or a clear resolution to the confusion expressed.

Contextual Notes

Participants note the forum's rules regarding the demonstration of effort before seeking help, which has led to some tension in the conversation. The original poster's repeated requests for hints indicate a struggle with the problem's complexity.

hubrisos
Messages
3
Reaction score
0
Homework Statement
A conducting sphere of radius a is made up of 3 different shells, upper part a/2 \leq z \leq -a/2, the middle part -a/2 \leq z\leq a, the lower part -a \leq z \leq -a/2 where the center of the sphere is at the origin. The upper part V and the lower part has -V potentials, while the mid part is grounded. Find the electric potential at x up to a 4 T order in the expansion of a/x << 1.



Basically the shell has 3 regions, upper, middle, lower. the lower/upper parts are not hemispherical, middle part is relatively broad, and the upper part has V, the lower part has -V potential.
Relevant Equations
green functions
A conducting sphere of radius a is made up of 3 different shells, upper part a/2
91fe1446-dc3f-4e80-a323-984eb2d97416.png
z
91fe1446-dc3f-4e80-a323-984eb2d97416.png
-a/2, the middle part -a/2
91fe1446-dc3f-4e80-a323-984eb2d97416.png
z
91fe1446-dc3f-4e80-a323-984eb2d97416.png
a, the lower part -a
91fe1446-dc3f-4e80-a323-984eb2d97416.png
z
91fe1446-dc3f-4e80-a323-984eb2d97416.png
-a/2 where the center of the sphere is at the origin. The upper part V and the lower part has -V potentials, while the mid part is grounded. Find the electric potential at x up to
323afa11-ef34-4ae4-907c-ae5e2581007f.png
order in the expansion of a/x << 1.

Basically the shell has 3 regions, upper, middle, lower. the lower/upper parts are not hemispherical, middle part is relatively broad, and the upper part has V, the lower part has -V potential.

I don't know where to start, I don't ask you to solve the entire thing, but give me a few tips/hints. I am lost due to the fact that the mid part is huge.
 

Attachments

  • hem.jpg
    hem.jpg
    16.1 KB · Views: 188
Physics news on Phys.org
hubrisos said:
I don't know where to start, I don't ask you to solve the entire thing, but give me a few tips/hints. I am lost due to the fact that the mid part is huge.
Can you be more specific? Why is that throwing you? Your thread title is "Method of image with Green function." That seems to suggest the approach you're supposed to take.
 
Gee why did not I think of that? Wow such an insight.
Thank you.
What a toxic community...
 
Well, the rules of the forum are that you need to show some effort, that you actually thought about the problem. "I have no idea where to start" doesn't cut it.
 
I did not ask you to solve the whole problem, did I?

I was a member of this website 5-6 years ago, and the same smug attitude was flying around everywhere. it seems it is still the same.

Enjoy your "I know everything" attitude. I am out.
 
hubrisos said:
I was a member of this website 5-6 years ago, and the same smug attitude was flying around everywhere. it seems it is still the same.
Our rules are still the same. As @vela said, you need to have shown some effort, at least to the point of thinking about an approach.
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
6K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 7 ·
Replies
7
Views
6K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
18
Views
2K