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Methods for solving simultaneous equations

  1. Jun 18, 2009 #1
    Hey everyone. Okay, first of all I'm not sure if these equations are simultaneous or linear so please correct me if I'm wrong. I need to know a simple procedure to tackle on these equations.Thanks.

    a) y=x-6 and y=2x-14
    b) y=0.5x-7 and y=3x-22
    c) 9y-4x+6=0 and 4x-2y-7=0
     
  2. jcsd
  3. Jun 18, 2009 #2

    CompuChip

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    Well, the first two are very easy because you have just "y" on the left hand side. Since obviously, y cannot have two different values at the same time, you must have y = y and therefore in the first case also x - 6 = 2x - 14 and in the second case 0.5x - 7 = 3x - 22. From this you can solve x in both cases, and then you just plug that value back in to also find y.

    The third case is a little more tricky. I suggest rewriting one of the equations to isolate either x or y, then plug that into the other equation so you get a single equation in a single variable. For example, you can rewrite the second one to 4x = .... and then replace the 4x in the first equation by that expression (watch out for the minus sign in front!)
     
  4. Jun 18, 2009 #3

    Borek

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    Alternatively - note, that on the left hand side of both equation you have 4x and -4x. If you add these equations side by side, x will cancel out.

    Quite often this can be done just by multiplying one of the equations by a constant. For example

    x + 2y = 7
    2x + 3y = 6

    multiply first equation by -2:

    -2x - 4y = -14

    add equations:

    -2x - 4y = -14
    2x + 3y = 6
    ----------------
    -y = -8

    You may as well multiply second equation by 2 and then subtract it from the first equation, it will give the same effect.
     
  5. Jun 18, 2009 #4
    Thank you so very much. That third one really made me scratching my head. Are you able to give me the order of operation to rewrite the 4x= please?
     
  6. Jun 18, 2009 #5
    THanks. So you're saying all i have to do is just add the equations for c) together?
     
  7. Jun 18, 2009 #6

    Borek

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    Try it.
     
  8. Jun 18, 2009 #7
    I don't know what i keep doing wrong. I keep getting 7y=1
     
  9. Jun 18, 2009 #8
    Oi dude, my Maths B exam is tomorrow and i need to know this question please
     
  10. Jun 18, 2009 #9
    its alright, ii finally got it. Thanks
     
  11. Jun 18, 2009 #10

    Borek

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    Good :smile:

    I was AFK, but I see you managed to get it right on your own.
     
  12. Jun 18, 2009 #11

    HallsofIvy

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    For (c), the simplest way is to notice that the two equations, 9y-4x+6=0 and 4x-2y-7=0 Have "4x" and "-4x". If you add the two equations, they cancel leaving (9-2)y+ (6-7)= 0 or 7y- 1= 0. Then 7y= 1 so y= 1/7. Replace y in either of the original equations to get a single equation to solve for x.

    By the way, the equations are both "simultaneous" (because there is more than one equation) and "linear" (because you have no powers of x and y except [itex]x^1= 1[/itex] and [itex]y^1= y[/itex] or more complicated functions of x and y.
     
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