Methods of integration: direct and indirect substitution

Click For Summary

Discussion Overview

The discussion centers on two approaches to the method of integration by substitution, referred to as direct substitution and indirect substitution. Participants explore the differences between these methods, their applications, and the terminology used in various contexts.

Discussion Character

  • Technical explanation
  • Debate/contested

Main Points Raised

  • Some participants describe Approach I as a method of integration by direct substitution, where the integral is transformed by substituting a function φ(x) with a new variable z.
  • Others suggest that Approach II is essentially Approach I in reverse, raising questions about its utility outside specific problems.
  • One participant notes that while Approach I is widely used, Approach II may not be commonly recognized terminology in the USA, referencing a source that uses the term "indirect substitution."
  • Another participant explains that both approaches express the same mathematical relationship but differ in how they are framed, emphasizing the role of pattern recognition in choosing substitutions.

Areas of Agreement / Disagreement

Participants express differing views on the terminology and utility of Approach II, with no consensus on its significance compared to Approach I. The discussion remains unresolved regarding the broader acceptance of these terms and methods.

Contextual Notes

There are references to specific sources that use different terminologies and interpretations of the substitution methods, indicating a potential variation in understanding based on educational context.

donaldparida
Messages
146
Reaction score
10
I have seen two approaches to the method of integration by substitution (in two different books). On searching the internet i came to know that Approach I is known as the method of integration by direct substitution whereas Approach II is known as the method of integration by indirect substitution.

Approach I

Let I=∫f(φ(x))φ'(x)dx

Let z=φ(x)

∴φ'(x)dx=dz

∴I=∫f(z)dz

Approach II


Let I=∫f(x)dx

Let x=φ(z)

∴dx=φ'(z)dz

∴I=∫f(φ(z))φ'(z)dz

My problem: While i can understand Approach I, I cannot understand Approach II. What is the difference between the two approaches. What is the difference in their usage. I very confused. Please help.
 
Physics news on Phys.org
Approach II seems to be approach I in reverse order. It is possible that it (II) is meaningful for a specific problem, but otherwise it doesn't seem to have much point. Approach I is widely used.
 
mathman said:
Approach I is widely used.

Approach II could be interpreted as what a calculus student encounters. The student must find a useful ##\phi(z)##.

donaldparida said:
whereas Approach II is known as the method of integration by indirect substitution.

To me (in the USA) "integration by indirect substitution" is not commonly used terminology. I find this web page https://www.askiitians.com/iit-jee-indefinite-integral/indirect-substitution/ where the terminology is used. (It also uses "integral" to mean "antiderivative".) The method presented on that page could be in interpreted as your Approach I instead of Approach II.
 
If we are finding ##\int H(x)dx## and wish to make a substitution to introduce a new variable ##z##, we can write the relation between ##x## and ##z## in two equivalent ways. We can write it as ##g(z) = x## or ##g^{-1}(x) = z## where ##g^{-1}## is the inverse function of ##g##.

The two Approaches differ in how they choose to express the same relationship. Visualize the ##\phi## in Approach I as denoting the inverse function of the ##\phi## in Approach II and you can see the approaches are doing the same thing mathematically. They both replace ##x## by some function of another variable.

The two Approaches differ as techniques of pattern recognition. When ##H(x)## is an expression we recognize as containing the product of a function with its derivative such as ##(... (sin(x))^2 + ...) ( cos(x))## we try the substitution ##z = sin(x)##. When ##H(x)## is not obviously of that form we might try the substitution ##x = arcsin(z)## just to see what happens. The equations ##z = sin(x)## and ##x = arcsin(z) ## express the same substitution.
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 14 ·
Replies
14
Views
4K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 17 ·
Replies
17
Views
5K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 22 ·
Replies
22
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K