(Methods)Parameters v Undetermined Coefficients

Click For Summary
SUMMARY

The discussion clarifies the distinction between the Method of Undetermined Coefficients and the Variation of Parameters in solving differential equations. The Method of Undetermined Coefficients is effective when the particular integral can be guessed, typically involving functions like e^{ax}, sin(ax), and cos(ax). However, for more complex functions such as tan(x) or 1/(1+x), the Variation of Parameters is necessary. This highlights the limitations of the former method and the scenarios where the latter is required.

PREREQUISITES
  • Understanding of differential equations
  • Familiarity with the Method of Undetermined Coefficients
  • Knowledge of Variation of Parameters
  • Basic calculus concepts, including integration and function behavior
NEXT STEPS
  • Study the Method of Undetermined Coefficients in detail
  • Learn about the Variation of Parameters technique
  • Explore examples of differential equations requiring both methods
  • Investigate the limitations and advantages of each method in practical applications
USEFUL FOR

Students and professionals in mathematics, particularly those focusing on differential equations, as well as educators seeking to explain these methods effectively.

hils0005
Messages
61
Reaction score
0
[SOLVED] (Methods)Parameters v Undetermined Coefficients

Can anyone tell me why I would use one technique over the other? It seems as though undetermined Coef. is much easier to do but I suppose that comes with limitations?
 
Physics news on Phys.org
hils0005 said:
Can anyone tell me why I would use one technique over the other? It seems as though undetermined Coef. is much easier to do but I suppose that comes with limitations?

Well if you can guess the particular integral of a Diff eq'n then method of undetermined coefficients will work and the pi's you can usually guess are usually e^{ax},sinax,cosax,sinax+cosax,etc.. But if you have tanx or \frac{1}{1+x} then you'll need to use variation of parameters to solve.
 
Thanks for the explanation
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
2K
Replies
3
Views
2K
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
12K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 4 ·
Replies
4
Views
4K
  • · Replies 11 ·
Replies
11
Views
11K