Metric Tensor in Spherical Coordinates

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I recently derived a matrix which I believe to be the metric tensor in spherical polar coordinates in 3-D. Here were the components of the tensor that I derived. I will show my work afterwards:

g₁₁ = sin²(ø) + cos²(θ)

g₁₂ = -rsin(θ)cos(θ)

g₁₃ = rsin(ø)cos(ø)

g₂₁ = -rsin(θ)cos(θ)

g₂₂ = r²sin²(ø) + r²sin²(θ)

g₂₃ = 0

g₃₁ = rsin(ø)cos(ø)

g₃₂ = 0

g₃₃ = r²cos²(ø)

The above is what I derived, but when I tried to verify to see if my answer was correct by checking various websites, I did not see any site have what I derived.

Here is my work:

The axes were:

x¹ = r

x² = θ

x³ = ø

The vector that I differentiated was:

<rcos(θ)sin(ø) , rsin(θ)sin(ø) , rcos(θ)>

I then differentiated the vector with respect to the various axes in order to derive my tangential basis vectors.

Here were my basis vectors:

e_r = <cos(θ)sin(ø) , sin(θ)sin(ø), cos(θ)>

e_θ = <-rsin(θ)sin(ø), rcos(θ)sin(ø) , -rsin(θ)>

e_ø = <rcos(θ)cos(ø), rsin(θ)cos(ø) , 0>

Finally, I did the dot product with these basis vectors to derive the components of my metric tensor.

That is how I got what I derived, but I don't see any confirmation of this online.

Can anyone please either verify if I am right with this metric tensor or tell me where I went wrong?

 

[Bill_K]

The vector that I differentiated was:

<rcos(θ)sin(ø) , rsin(θ)sin(ø) , rcos(θ)>

The transformation to spherical polar coordinates is

x = r sin(θ) cos(ø)
y = r sin(θ) sin(ø)
z = r cos(θ)

r = <r sin(θ) cos(ø), r sin(θ) sin(ø), r cos(θ)>

 

[space-time]

The transformation to spherical polar coordinates is

x = r sin(θ) cos(ø)
y = r sin(θ) sin(ø)
z = r cos(θ)

r = <r sin(θ) cos(ø), r sin(θ) sin(ø), r cos(θ)>

So I made a careless mistake it seems. Thank you Bill K.