Minimising the action for surface area in AdS

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Discussion Overview

The discussion revolves around minimizing an action integral related to a function U(r) in the context of AdS (Anti-de Sitter) space. Participants explore methods for solving a second-order nonlinear differential equation derived from the Euler-Lagrange equations, considering various approaches including Hamiltonian mechanics and Noether's Theorem.

Discussion Character

  • Exploratory
  • Technical explanation
  • Mathematical reasoning

Main Points Raised

  • One participant presents an action integral that requires minimization and expresses difficulty in solving the resulting differential equation.
  • Another participant seeks clarification on the variables involved, specifically questioning the function of U and the limits of integration.
  • A later reply corrects a potential misunderstanding regarding the notation and specifies the integration limits, while also suggesting a possible form for U(r).
  • There is a suggestion that the integral could be zero with an appropriate choice of U and U', although the specific choice remains unspecified.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the best method to derive U(r), and multiple approaches are discussed without resolution.

Contextual Notes

The discussion includes uncertainties regarding the choice of U and the implications of the integration limits, as well as the potential for the integral to evaluate to zero under certain conditions.

mattie_p
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Hello people.
I've got an action which needs minimising

[tex]\int dr \ r \sqrt{U'^{2}+U^{4}}[/tex]

Where U(r). Simply plugging this into the EL equations yields a nasty looking 2nd order nonlinear differential equation. I'm just wondering if there's an easier way of solving for U(r). I've tried passing over into Hamiltonian mechanics but that seemed to confuse matters slightly (I probably got it wrong). Wondering if there's some implementation of Noether's Theorem that could give a solvable differential equation. As always, much thanks for your help.
 
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I see integral w.r.t. tau and U is a function of what? r?
 
I see integral w.r.t. tau and U is a function of what? r?
BTW: What is the interval of integration?
 
Hey, thanks for having a look at this,
I think latex has just made the r look like a tau. It's meant to read
Integral dr*r*(U'^2 + U^4)^1/2

Also, the integration region is between 0 and some constant L, but that will lead to an inifinity, so the problem is actually integrated between 0 and (L^2-c^2)^1/2. I know the answer is roughly U(r)=(L^2-r^2)^-1/2, but my real problem is trying to derive this.
 
Well, it seems the integral may very well be zero with the right choice of U' and U over an interval of positive r. Considering the even powers involved, there are not many choices other than U= (?)




























ans: U=0 (identically).
 

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