- #1
CGMath
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An area A in the (x,y) plane is limited by the y-axis and a parabola with the equation x=6-y^2. Further, is a surface F given by the part of the graph for the function h(x,y)=6-x-y^2 which satisfies the conditions x>=0 and z>=0.
Determine a parametrization for A and for F.
So far I've got the parametrization for A, which i got to r(u,v)=(6-v^2,v), v ∈ [0,6].
My attempt of a solution for F is r(u,v)=(u,v, 6-u-v^2), but i am not sure about the limits of each parameter and if it's the correct parametrization. Could someone help me out?
Thanks!
Determine a parametrization for A and for F.
So far I've got the parametrization for A, which i got to r(u,v)=(6-v^2,v), v ∈ [0,6].
My attempt of a solution for F is r(u,v)=(u,v, 6-u-v^2), but i am not sure about the limits of each parameter and if it's the correct parametrization. Could someone help me out?
Thanks!