Minimizing Total Cost of Making Open Box with Squared Base

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SUMMARY

The discussion focuses on minimizing the total cost of constructing an open box with a squared base, given a volume constraint of 6400 cm3. The total cost (TC) is defined as TC = x2 + 0.5xy, where x is the base dimension and y is the height. A participant suggests solving the volume constraint for y and substituting it into the TC function to minimize cost as a function of x, negating the need for Lagrange multipliers. This approach leads to a more straightforward solution for determining the optimal dimensions.

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Homework Statement


We want to make an open box with squared base. Let x be the dimension of one side of the base and y the height of the box. We pay a cost of $1.00 /cm^2 for the base and $0.50/cm^2 for each side.
The box must have a volume V = 6400 cm^3. Determine the dimensions x and y which will minimize the total cost of making the box.


Homework Equations


V = yx^2, TC = x^2 + 0.5xy


The Attempt at a Solution


I tried to solve the problem taking the partial derivatives with respect to x and y, which will give me the minimum values, but my results are not consistent. I am thinking on using Lagrange multipliers to solve the nonlinear minimization problem subject to the equality constraint of volume.
Any suggestions?
Thank you.
 
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In your TC function, remember that the box has four sides. Solve the volume constraint for, say, y. Then substitute that into TC. Now total cost is a function of only x. Minimize it. You certainly don't need lagrange multipliers.
 
Thank you, I think this works.
 

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