Minimum Force for Overcoming Friction on a Wooden Box

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SUMMARY

The minimum force required to overcome friction on a 20 kg wooden box pushed across a horizontal stone floor is calculated using the coefficient of kinetic friction, which is 0.40. The force of friction can be determined using the formula F_friction = μ * N, where μ is the coefficient of kinetic friction and N is the normal force. Given that the normal force equals the weight of the box (N = mass * gravity), the minimum force required is 78.4 Newtons.

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  • Understanding of Newton's laws of motion
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  • Basic algebra for solving equations
  • Familiarity with the concept of normal force
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Homework Statement



A 20 kg wooden box is pushed a distance of 15 meters on a horizontal stone floor, by a force just sufficient to overcome the friction between the box and floor. The coefficient of kinetic energy is 0.40. What is the minimun force required?

Thanks.
 
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