Minimum force required to keep two blocks from not falling

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Homework Help Overview

The discussion revolves around a physics problem involving two blocks and the minimum force required to prevent them from falling. The subject area includes concepts of friction and forces acting on the blocks.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the relationship between the maximum friction force and the forces needed to keep the blocks from sliding. Questions arise regarding the necessity of calculations for both blocks, particularly in relation to their weights and the friction involved.

Discussion Status

The discussion is ongoing, with participants providing insights into the calculations and reasoning behind the forces at play. Some guidance has been offered regarding the calculations needed for block P, although no consensus has been reached on the necessity of these calculations.

Contextual Notes

There is mention of specific values for friction and weight, but the overall context of the problem may be limited by assumptions about the setup and the forces involved.

nafisanazlee
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Homework Statement
Two blocks P and Q are of weight 20N and 100N, respectively. These are being pressed against a wall by a force F as shown. If the coefficient of static friction between the blocks is 0.1 and between block Q and the wall is 0.15, what will be the minimum force to keep the blocks in equilibrium?
I've tried to solve it in this way, but I'm not sure if my approach is correct or not. Can you please check?
Relevant Equations
Fsmax = μsN
CamScanner 11-26-2023 02.56.jpg
 
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:welcome:

Looks right. You might want to add why block P does not slide.
 
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PeroK said:
:welcome:

Looks right. You might want to add why block P does not slide.
because the maximum friction force that can be provided between the two blocks becomes 0.1*800= 80N, and we only need 20N for support, so it's fine..?
 
nafisanazlee said:
because the maximum friction force that can be provided between the two blocks becomes 0.1*800= 80N, and we only need 20N for support, so it's fine..?
Yes, it was fairly obvious from the numbers that the maximum force was needed for Q (as it is much heavier). But, it does no harm to show the calculation for P as well.
 
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PeroK said:
Yes, it was fairly obvious from the numbers that the maximum force was needed for Q (as it is much heavier). But, it does no harm to show the calculation for P as well.
Thank you so much for your time. Much appreciated.
 
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