MINIMUM force that a technician must exert on this wrench to deliver this torque

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SUMMARY

The minimum force required for a technician to deliver a torque of 150 N/m using a wrench with a handle length of 0.03 m is calculated to be 5000 N, derived from the formula F = T/r. A larger force can achieve the same torque by either increasing the wrench length or applying force further from the bolt. In weightless environments, such as underwater or in space, applying torque becomes more challenging due to the lack of gravitational force to stabilize the wrench. The discussion also covers energy calculations for a vehicle navigating a dune and the dynamics of a pendulum, emphasizing the principles of energy conservation and momentum.

PREREQUISITES
  • Understanding of torque and its calculation (Torque = Force x Distance)
  • Basic principles of energy conservation (Kinetic and Potential Energy)
  • Newton's Laws of Motion, particularly momentum conservation
  • Concept of centripetal and centrifugal forces in circular motion
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  • Learn about torque calculations in mechanical systems
  • Study energy conservation principles in physics
  • Explore momentum conservation in collisions and interactions
  • Investigate the effects of gravitational forces in different environments
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Physics students, mechanical engineers, technicians, and anyone interested in understanding the principles of torque, energy, and momentum in practical applications.

physicszman
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1) A manual specifies that certain bolts are to be tightened to a torque of 150 N/m.

a) Using a wrench whose handle is .03 m long. what is the MINIMUM force that a technician must exert on this wrench to deliver this torque.

b) Make a drawing to show how this is possible that the same torque could result from even a larger force using the same wrench.


c) Explain why application of a torque like this will be more difficult for a scuba diver floating under water or an astronaut orbiting in space than it will be for a person standing on the shop floor.


2) A driver in a 1000kg sport-utility vehicle needs to keep moving with a speed of at least 10m/s to avoid getting bogged down in sand. Entering a sand area at 20 m/s. the driver approaches a dune whose top is 10 m above her current position. The length of the trail up to the top is 100m and there is a substantial, 3000N drag force from the sand.

how much energy must be obtained from combustion of fuel in the engine to get to the top with a speed of at least 10 m/s along this trail?


3) A 2.0 Kg object is tied to a 3.0 m long rope so that it swings like a simple pendulum. At the lowest point in its path, the mass is moving 4.0 m/s. If we can neglect the mass of the rope and assume that the effects of swing through the air are so small they can be ignored:

a) How high above the lowest point will this mass rise before stopping?

b) What will be its speed when it swings back down through the lowest point on its return path?

c) If this is set up as a demonstration, describe how measured values for A and B can be expected to compare with what was computed.


4) A 10,000 kg railroad car is rolling freely north along a level trach at 5.0 m/s. AS it passes under a sand hopper, 30,000 kg of sand is dropped down into the car. A short time later, a hatch is opened at the bottom of the car and the sand is allowed to drain out downward.

a) What is the momentum of the car before it is loaded?

b) What is the momentum of the car and its load of sand?

c) What is the momentum of the car after it is emptied?


5) A possible origin for the material found in the rings of Saturn is a moon that got torn apart by tidal forces/

a) Male a sketch showing a planet and use Newton's Law of Universal Gravitation to explain why tidal forces exist.

b) Show that these forces will become greater if the moon approches the planet.

6) a) Deescribe the condidions under which a centripetal force appears to exist.

b) Explain how a centrifugal force could appear to exist in this situation.


7) COnsider an Apollo program spacecraft that is approaching the moon. The command module of the spacecraft should stay in a stable orbit at an altitude of 111 km above the surface of the moon. With G - 6.67 x 10^-11N M^2/kg^2 and the Moon's mass of 7.4 x 10^22 kg and radius of about 1.7 x 10^6m.

a) What will be the period of the command module in this orbit?

b) If the spacecraft was traveling 40,000 km/hr during approach, was this speed fast, too slow or just right for their orbit. Explain.
 
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Originally posted by physicszman
1) A manual specifies that certain bolts are to be tightened to a torque of 150 N/m.


a) Using a wrench whose handle is .03 m long. what is the MINIMUM force that a technician must exert on this wrench to deliver this torque.
You don't need help with a question this simple

b) Make a drawing to show how this is possible that the same torque could result from even a larger force using the same wrench.
Apply a greater force but the force should be closer to the nut.


c) Explain why application of a torque like this will be more difficult for a scuba diver floating under water or an astronaut orbiting in space than it will be for a person standing on the shop floor.
A guy on a floor has a good footing. People in space or under water will just move themselves when they try to apply a force.


2) A driver in a 1000kg sport-utility vehicle needs to keep moving with a speed of at least 10m/s to avoid getting bogged down in sand. Entering a sand area at 20 m/s. the driver approaches a dune whose top is 10 m above her current position. The length of the trail up to the top is 100m and there is a substantial, 3000N drag force from the sand.


how much energy must be obtained from combustion of fuel in the engine to get to the top with a speed of at least 10 m/s along this trail?
summ of energies. Fd for the drag in the sand, mgh for the hill. if you have to run at 10m/s and you are going 20m/s, that means you can afford to lose 10m/s. find the energy that the suv loses from a change of 10m/s.
fuel = Fd (sand) + mgh (hill) - (1/2)mv^2 (amount of extra kinetic energy the suv has)

3) A 2.0 Kg object is tied to a 3.0 m long rope so that it swings like a simple pendulum. At the lowest point in its path, the mass is moving 4.0 m/s. If we can neglect the mass of the rope and assume that the effects of swing through the air are so small they can be ignored:

a) How high above the lowest point will this mass rise before stopping?
(1/2)mv^2 = mgh

b) What will be its speed when it swings back down through the lowest point on its return path?
4m/s

c) If this is set up as a demonstration, describe how measured values for A and B can be expected to compare with what was computed.
the real values will be different because true 100% efficiency does not exist.


4) A 10,000 kg railroad car is rolling freely north along a level trach at 5.0 m/s. AS it passes under a sand hopper, 30,000 kg of sand is dropped down into the car. A short time later, a hatch is opened at the bottom of the car and the sand is allowed to drain out downward.

a) What is the momentum of the car before it is loaded?
you don't need help to find this

b) What is the momentum of the car and its load of sand?
the same

c) What is the momentum of the car after it is emptied?
find the velocity of the cart after it was loaded with sand then multiply that velocity by the weight of the cart only.


5) A possible origin for the material found in the rings of Saturn is a moon that got torn apart by tidal forces/

a) Male a sketch showing a planet and use Newton's Law of Universal Gravitation to explain why tidal forces exist.

b) Show that these forces will become greater if the moon approches the planet.
I can't help with that. Sorry.

6) a) Deescribe the condidions under which a centripetal force appears to exist.
when an object is moving in a circular motion, is connected to something else and it has mass.

b) Explain how a centrifugal force could appear to exist in this situation.
The term centrifugal itself means "directed away from the axis", thus, centrifugal force means the force is pushing away from the axis. Seeing 'centrifugal' force depends on what you are referring to. Centrifugal force is exerted on whatever is the axis. The force acting on the object is centripetal.

7) COnsider an Apollo program spacecraft that is approaching the moon. The command module of the spacecraft should stay in a stable orbit at an altitude of 111 km above the surface of the moon. With G - 6.67 x 10^-11N M^2/kg^2 and the Moon's mass of 7.4 x 10^22 kg and radius of about 1.7 x 10^6m.

a) What will be the period of the command module in this orbit?

b) If the spacecraft was traveling 40,000 km/hr during approach, was this speed fast, too slow or just right for their orbit. Explain.

Sorry but I can't help with these.
 
Last edited:


a) The MINIMUM force that a technician must exert on the wrench to deliver a torque of 150 N/m can be calculated using the formula F = T/r, where F is the force, T is the torque, and r is the length of the wrench handle. So, for a wrench with a handle length of 0.03 m, the minimum force would be 150 N/m divided by 0.03 m, which is equal to 5000 N.

b) A larger force could also deliver the same torque by either using a longer wrench handle or by applying the force at a greater distance from the bolt. For example, if the technician uses a wrench with a handle length of 0.06 m, the force required would be 2500 N. This is because the longer handle would require less force to apply the same amount of torque. Similarly, if the force is applied at a greater distance from the bolt, it would require less force to deliver the same torque.

c) Application of torque in a weightless environment, such as underwater or in space, would be more difficult because there is no gravitational force to help hold the wrench in place. The technician would need to use their own strength and body positioning to keep the wrench in place and apply the required torque. This would require more effort and could be challenging in a weightless environment.

2) To calculate the energy required to get to the top of the dune, we can use the formula KE = 1/2mv^2, where KE is the kinetic energy, m is the mass of the vehicle, and v is the velocity. The energy needed to overcome the drag force can be calculated by multiplying the drag force by the distance traveled. So, the total energy required would be the sum of these two energies.

3) a) To calculate the height above the lowest point, we can use the formula PE = mgh, where PE is the potential energy, m is the mass, g is the acceleration due to gravity, and h is the height. We can rearrange this formula to solve for h, which gives us h = PE/mg. So, the height would be equal to the potential energy (which is equal to kinetic energy at the lowest point) divided by the mass and the acceleration due to gravity.

b) The speed at the lowest point on the return path would be equal to the speed at the lowest point on the initial path, as there is
 

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