Minimum Force to Move 6kg Object on Friction Surface

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To determine the minimum force required to move a 6 kg object on a surface with a coefficient of friction of 0.8, the equations of motion and friction must be applied. The normal force (N) and friction force (fr) are critical, with fr calculated as the product of the coefficient of friction and N. The discussion highlights the importance of a specific angle (theta) that minimizes the force needed to initiate movement, which varies based on the applied force and mass. The user expresses confusion over the unknowns in their equations, particularly N and theta, while seeking clarification on their approach. The consensus is that the user is on the right track but may need to simplify their equations to isolate the variables effectively.
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Homework Statement


A 6 kg object sits on a horizontal surface with coefficient of friction = .8. What is the minimum force (not necessarily horizontal) necessary to make the object slide?

Homework Equations


fr = u * N
where fr = the friction force
u = coefficient of friction
N = the normal force

The Attempt at a Solution


I knew there was something more to this problem- In lecture, my prof talked about a "magic" angle theta in the positive x and positive y direction that would take the least amount of force to move an object is one was pulling on the object at said "magic" angle. Since no value was mentioned, I assume the angle varies with the mass and the force being applied to the object.

As usual for me, I have an apparently sound free body diagram, apparently sound equations, and too many unknowns. I have normal force N, force of gravity mg, friction force fr, and the force on the object F.

Fnet,x = F cos theta - fr = ma
(my prof doesn't believe in the difference between Fk and Fs (static and kinetic friction) so when a = 0 is when the minimum force is being exerted to make the block move)
Fnet,x = F cos theta = fr
Fnet,y = N - mg + F sin theta = ma
acceleration is zero in the y direction so:
F sin theta = mg - N

I can sub in u * N for fr and set tan theta equal to (mg - N) / (u * N), but I don't know N or theta and I'm trying to get to F.

Am I approaching these problems wrong or do I just keep getting lost along the way? I feel like I keep getting stuck in the same places.
 
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uchicago2012 said:
Fnet,x = F cos theta - fr = ma
(my prof doesn't believe in the difference between Fk and Fs (static and kinetic friction) so when a = 0 is when the minimum force is being exerted to make the block move)
Fnet,x = F cos theta = fr
Fnet,y = N - mg + F sin theta = ma
acceleration is zero in the y direction so:
F sin theta = mg - N
Looks good to me, so far.

I can sub in u * N for fr
Definitely.

and set tan theta equal to (mg - N) / (u * N), but I don't know N or theta and I'm trying to get to F.
Eliminate N. Solve for F in terms of theta.

Am I approaching these problems wrong or do I just keep getting lost along the way? I feel like I keep getting stuck in the same places.
These are tricky. You're doing fine. Keep playing with it.
 
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