Minimum Force to Move 6kg Object on Friction Surface

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SUMMARY

The minimum force required to move a 6 kg object on a horizontal surface with a coefficient of friction of 0.8 can be calculated using the equations of motion and friction. The friction force (fr) is determined by the equation fr = u * N, where u is the coefficient of friction and N is the normal force. The optimal angle (theta) for applying force to minimize the effort needed to overcome friction is crucial, as it affects the distribution of forces in both the x and y directions. By eliminating the normal force (N) and solving for the applied force (F) in terms of theta, one can derive the necessary force to initiate movement.

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uchicago2012
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Homework Statement


A 6 kg object sits on a horizontal surface with coefficient of friction = .8. What is the minimum force (not necessarily horizontal) necessary to make the object slide?

Homework Equations


fr = u * N
where fr = the friction force
u = coefficient of friction
N = the normal force

The Attempt at a Solution


I knew there was something more to this problem- In lecture, my prof talked about a "magic" angle theta in the positive x and positive y direction that would take the least amount of force to move an object is one was pulling on the object at said "magic" angle. Since no value was mentioned, I assume the angle varies with the mass and the force being applied to the object.

As usual for me, I have an apparently sound free body diagram, apparently sound equations, and too many unknowns. I have normal force N, force of gravity mg, friction force fr, and the force on the object F.

Fnet,x = F cos theta - fr = ma
(my prof doesn't believe in the difference between Fk and Fs (static and kinetic friction) so when a = 0 is when the minimum force is being exerted to make the block move)
Fnet,x = F cos theta = fr
Fnet,y = N - mg + F sin theta = ma
acceleration is zero in the y direction so:
F sin theta = mg - N

I can sub in u * N for fr and set tan theta equal to (mg - N) / (u * N), but I don't know N or theta and I'm trying to get to F.

Am I approaching these problems wrong or do I just keep getting lost along the way? I feel like I keep getting stuck in the same places.
 
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uchicago2012 said:
Fnet,x = F cos theta - fr = ma
(my prof doesn't believe in the difference between Fk and Fs (static and kinetic friction) so when a = 0 is when the minimum force is being exerted to make the block move)
Fnet,x = F cos theta = fr
Fnet,y = N - mg + F sin theta = ma
acceleration is zero in the y direction so:
F sin theta = mg - N
Looks good to me, so far.

I can sub in u * N for fr
Definitely.

and set tan theta equal to (mg - N) / (u * N), but I don't know N or theta and I'm trying to get to F.
Eliminate N. Solve for F in terms of theta.

Am I approaching these problems wrong or do I just keep getting lost along the way? I feel like I keep getting stuck in the same places.
These are tricky. You're doing fine. Keep playing with it.
 

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