What is the minimum height of the bag needed for glucose infusion?

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SUMMARY

The minimum height of a collapsible plastic bag needed for glucose infusion, given an average gauge pressure of 15000 Pa and a specific gravity of 1.04, is calculated using the formula P = ρgh. By substituting the specific gravity to obtain the density (1040 kg/m³) and using the acceleration due to gravity (9.8 m/s²), the height is determined to be 1.47 meters. The discussion emphasizes the importance of including units in calculations, particularly for specific gravity, which is a unit-less ratio of densities.

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Homework Statement



A collapsible plastic bag contains a glucose solution. If the average gauge pressure in the vein is 15000 Pa, what must be the minimum height of the bag in order to infuse glucose into the vein? Assume that the specific gravity of the solution is 1.04. The acceleration of gravity is 9.8 m/s2. Answer in units of m.

Homework Equations



P=\rhogh

The Attempt at a Solution



I don't know what the units of the specific gravity so I assumed its 1.04 g/c,3. So it becomes 1040 kg/m3.

So would it be:

P=\rhogh

15000 Pa = (1040 kg/m3)(9.80 kg m/s2)h
\frac{15000 Pa}{1040*9.80} = h
1.47 = h

Is that right? TIA
 
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It looks correct.

But do tell your teacher that NO value should be given without its units. (i'm obviously referring to the "1.04" for the specific gravity.)R.
 
Its correct! So what would be the usual units for specific gravity? TIA
 
I would have guessed g/cm^3 as you did.
But purely because the value was close to 1.
(The density of water is 1g/cm^3).
 
Rick88 said:
I would have guessed g/cm^3 as you did.
But purely because the value was close to 1.
(The density of water is 1g/cm^3).

Specific gravity is unit-less. It's a ratio of densities. That's what makes it "specific".

In most cases it's a ratio of the density of the given substance to the density of water.
 
Oh, of course.

Thanks for that, gneill.
 
Thank you gneill!
 

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