1. The problem statement, all variables and given/known data A large tank of water has a 'z-shaped' hose connected to it. The tank is sealed at the top and has compressed air between the water surface and the top. When the water height, h, has the value 3.50m, the absolute pressure p of the compressed air is 4.20x10^5 Pa. Assume that the air above the water expands at a constant temperature, and take the atmospheric pressure to be 1.00x10^5 Pa. a)What is the speed with which the water flows out of the hose when h=3.50m? b)As water flows out of the tank, h decreases. Calculate the speed of flow for h=3.00m and h=2.00m c)At what value of h does the flow stop? 2. Relevant equations Bernoulli's eq. P1 + (1/2)ρ(v1)^2 + ρgh1 = P2 + (1/2)ρ(v2)^2 + ρg(h2) P1 + ρgh1 = P2 + (1/2)ρ(v2)^2 + ρg(h2) assuming viscosity is zero water is incompressible 3. The attempt at a solution p=4.2*105 Pa p2=1*105 Pa and h2=1m h=3.5m a.) v=√(2((p-1.0*105)/ρ)+g(h-h2))=.....≈26.2m/s b.) p=(0.5p1)/(4m-h) (pV=constant as the temperature is constant) and now h=3m v=√(2((p-1.0*105)/ρ)+g(h-h2))=√(2((p=(0.5p1)/(4m-h)-1.0*105)/ρ)+g(h-h2)) By substituting in new values for h I got 16.m/s and 5.44m/s both of which are right according to my book. However, the part c is confusing me a little. I have tried setting v=0 and solving for h but I didn't get the right answer which is h=1.78meters according to my book. I know somebody will ask me to show the calculations so I ended up having equation of second degree like gρh2-5gρ+(4gρ-0.5p1+p2)=0 I got h>4m or h<0 which make no sense at all. Any piece of advice will be appreciated.