Minimum speed to maintain a circular trajectory

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SUMMARY

The minimum speed required for a rock of mass 0.500 kg tied to a string of radius 75 cm to maintain a circular trajectory without the string collapsing is calculated using the formula v = √(g * r). With gravitational acceleration (g) approximated at 9.81 m/s², the minimum speed is determined to be 2.7 m/s. It is crucial to note that the weight of the rock is not the only force acting on it, and its direction varies throughout the trajectory.

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xxgaxx
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Homework Statement


a rock of mass 0.500 kg is tied to a string of radius 75 cm and is revolving in a vertical circle at a uniform speed. determine the minimum speed for the rock to maintain a circular trajectory without the string collapsing (not staying taut). (Hint: where would that occur in the trajectory?)

m=0.500 kg
r=.75 m



Homework Equations



mg=(mv^2)/r

The Attempt at a Solution



v=(gr)^(1/2) (square root of g*r)
v=2.7 m/s
i don't know where i use the mass of 0.500 kg
 
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xxgaxx said:

Homework Statement


a rock of mass 0.500 kg is tied to a string of radius 75 cm and is revolving in a vertical circle at a uniform speed. determine the minimum speed for the rock to maintain a circular trajectory without the string collapsing (not staying taut). (Hint: where would that occur in the trajectory?)

<snip>

mg=(mv^2)/r
Are you sure that the weight of the rock is the only force acting? Furthermore, are you sure that the weight of the rock always acts radially?
 

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