Minimum work to separate O2 &N2 from air

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    Air Minimum Work
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Homework Help Overview

The discussion revolves around calculating the minimum work required to separate oxygen (O2) and nitrogen (N2) from air, which is treated as an ideal gas at specified conditions. The mole fractions of the components in air are provided, and the problem is framed in terms of separating 1 kmol of each gas at 25°C and 100 kPa.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the application of the minimum work equation for ideal gases and express confusion regarding the separation of only O2 while considering the overall composition of air. Questions arise about the initial conditions necessary for the separation process and the implications of the provided mole fractions.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem. Some have attempted to apply relevant equations, while others are questioning the assumptions made about the air composition and the initial conditions for the separation process.

Contextual Notes

There is uncertainty regarding the amount of air needed for the separation calculations, and participants are considering the implications of including other components of air, such as water vapor and carbon dioxide, in their reasoning.

obscure
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1. assume air is an iseal gas at 25C and 100kPa. the mole fractions of components are nitrogen_0.7567
oxygen=0.2035 water vapor=0.0303 carbon dioxide=0.0003 Calc. min work to separate
a-1kmol O2 at 25C 100kPa
b-1kmol N2 at 25C 100kPa from atmosphere


Homework Equations


Wmin=ge-gi=(ho-To.se)-(hi-To.si) [/B]

The Attempt at a Solution


for ideal gas Wmin=To(si-se)=-R.To. total(Xi.lnxi)
I assume air is composed of only O2 and N2, min ork is equal to - of the entropy change for mixing process
but Iam confused it is asked only to separate 1 kmol O2
[/B]
 
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obscure said:
a-1kmol O2 at 25C 100kPa
b-1kmol N2 at 25C 100kPa
One kmol O2 and one kmol N2.
 
Bystander said:
One kmol O2 and one kmol N2.
1 kmol of oxygen at 25C and 100kPa and
1 kmol of nitrogenat 25C and 100kPa from atmosphere
 
obscure said:
3. The Attempt at a Solution
for ideal gas Wmin=To(si-se)=-R.To. total(Xi.lnxi)
I assume air is composed of only O2 and N2, min ork is equal to - of the entropy change for mixing process
but Iam confused it is asked only to separate 1 kmol O2
Why do you assume that? It gives the composition, and it includes water vapour and CO2.
Why does the question confuse you?
The thing that is not clear to me is how much air you should start with. Perhaps the answer tends to a limit as the initial number of moles tends to infinity.
 
Bystander said:
One kmol O2 and one kmol N2.
Yes, but not from the same air sample. They are presented as two independent questions.
 

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