- #1

Firecloak

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## Homework Statement

The highest achievable resolving power of a microscope is limited only by the wavelength used; that is, the smallest item that can be distinguished has dimensions about equal to the wavelength. Suppose one wishes to "see" inside an atom. Assuming the atom to have a diameter of 100 pm, this means that one must be able to resolve a width of, say, 10 pm.

(a) If an electron microscope is used, what minimum electron energy is required?

## Homework Equations

E = hc/λ

λ = h/p (DeBroglie wavelength)

p=sqrt(2mK) Momentum

Δλ = (h(1-cos θ))/mc Compton Shift

## The Attempt at a Solution

I tried the equation E = hc/λ = (6.63e-34)(3e8)/(1e-12) = 1.24e6 eV, but that isn't the answer.