Mirror 4-Momentum: Find Frequency Change on Reflection

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SUMMARY

The discussion centers on the reflection of light from a moving mirror, specifically analyzing the frequency change of light upon reflection. The mirror moves perpendicular to its plane at speed βc, and the light ray's incident angle θ is measured with respect to the mirror's normal vector. The solution involves calculating the 4-momentum of the light before and after reflection, with the conclusion that in the mirror's rest frame, the angle of reflection equals the angle of incidence, resulting in no frequency shift.

PREREQUISITES
  • Understanding of special relativity concepts, particularly 4-momentum.
  • Familiarity with the Lorentz transformation and relativistic velocity addition.
  • Knowledge of light behavior in different reference frames.
  • Basic principles of reflection and refraction in physics.
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  • Study the derivation of 4-momentum in special relativity.
  • Learn about the Doppler effect in the context of moving mirrors.
  • Explore the implications of relativistic velocity addition on light reflection.
  • Investigate the behavior of light in non-inertial reference frames.
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Homework Statement


A mirror moves perpendicular to its plane with speed βc. A light ray is incident on the mirror from the “forward” direction (i.e., vm · vl < 0, where vm is the mirror’s 3-velocity and vl is the light ray’s 3-velocity) with incident angle θ (measured with respect to the mirror’s normal vector). (a) Find cos φ, where φ is the angle of reflection. (b) By what factor does the frequency of the light change upon reflection?

Homework Equations



None that I know of.

The Attempt at a Solution


P~ in = E c (sin θin , − cos θin , 0 , 1)
P~ ′ in = E c [γ(sin θin − β) , − cos θin , 0 , γ(1 − β sin θin)]
I don't know what else.
 
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What happens in the mirror rest frame when the light is reflected?
 
In the rest frame of the mirror the angle of reflection equals the angle of incidence and there is no frequency shift.
 
So what will be the 4-momentum of the light after reflection?
 
Well, I went to my teacher and found the answer. But thanks for your help anyways!
 

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