Mistake in Exercises for the Feynman Lectures?

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The discussion centers on the interpretation of the velocity components of a point on a rolling wheel, specifically focusing on the angle θ and its impact on velocity calculations. The initial assertion is that the velocity should be expressed as v = V((1+sinθ)i -(cosθ)j), based on the expected behavior of the wheel's motion. Clarification is sought on whether this expression accurately predicts the speed of point P on the rim relative to the ground contact point. The question highlights the relationship between the angle of rotation and the resulting velocity components. Ultimately, a misreading of the question is acknowledged, leading to a better understanding of the problem.
suh112
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Homework Statement
This is problem 14.1 from "Exercises for the Feynman Lectures on Physics":

14.1 A rigid wheel of radius R is rolling without slipping on a horizontal surface. The plane of the wheel is vertical, and the axis of the wheel is moving horizontally with a speed V relative to the surface. If the axis of the wheel is parallel to the z-axis, V is in the positive x-direction, and ##\theta## the angle through which the wheel has rotated since a certain point P on the rim was in contact with the ground, show that the instantaneous velocity (speed and direction) of the point P is given by
v = V ((1- cos##\theta##)i + (sin ##\theta##) j).
Relevant Equations
v = V ((1- cos##\theta##)i + (sin ##\theta##) j)
It seems to me that the answer should be v = V((1+sinθ)i -(cosθ)j) intuitively since ##V_x## should be zero at θ = −π\2 and should be greatest when the angle is 90 degrees. Similarly, the component of velocity in the y direction should be greatest when the angle ##\theta## is 180 degrees and zero when ##\theta## is 0 degrees. Am I doing something wrong?
 

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According to the statement of the question, angle θ is "the angle through which the wheel has rotated since a certain point P on the rim was in contact with the ground". If the wheel rolls without slipping what is the speed of certain point P on the rim relative to the point of contact with the ground? Does the given expression predict that? Does your expression predict that?
 
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kuruman said:
According to the statement of the question, angle θ is "the angle through which the wheel has rotated since a certain point P on the rim was in contact with the ground". If the wheel rolls without slipping what is the speed of certain point P on the rim relative to the point of contact with the ground? Does the given expression predict that? Does your expression predict that?
Oh I misread the question. This makes sense thanks.
 
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The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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