Mode of 1,1,2,2: Is it 1, 2, Both, or None?

  • Thread starter Thread starter r4nd0m
  • Start date Start date
  • Tags Tags
    Mode
Click For Summary

Homework Help Overview

The discussion revolves around determining the mode of the dataset consisting of the numbers 1, 1, 2, and 2. Participants are exploring the definition of mode and its implications in the context of this specific dataset.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are questioning whether the dataset has one mode, two modes, or none, given that both 1 and 2 appear with equal frequency. There is also confusion regarding the definitions of mode and median, as well as the implications of frequency in determining modal values.

Discussion Status

Some participants suggest that the dataset is bimodal, while others express uncertainty about the definition of mode and its application to this case. Clarifications about the frequency of occurrences and the nature of the dataset are being explored, but no consensus has been reached.

Contextual Notes

There is a lack of explicit frequency data provided, leading to assumptions about the occurrences of the numbers. Participants are also reflecting on their understanding of statistical terms, which may affect their interpretations.

r4nd0m
Messages
96
Reaction score
1
what is the mode (modus) of 1,1,2,2
I was checking the definition but it didn't count with two maximums.
So is it 1,5 or both 1 and 2, or none of them?
 
Physics news on Phys.org
This dataset is bimodal, in otherwords it has two modal values. 1 and 2 are both modal values.

~H
 
I thought mode was that event or observation that occurred most frequently.
In this case since the frequencies are not given (assumed to be 1), all the elements should be modes right ?
Or are you talking of median (middlemost value in magnitude) ?
 
arunbg said:
I thought mode was that event or observation that occurred most frequently.
In this case since the frequencies are not given (assumed to be 1), all the elements should be modes right ?
Or are you talking of median (middlemost value in magnitude) ?

But the '1' events are identical, as are the '2' events. They each occur with a frequency of two. So this distribution with N=4 is bimodal with '1' and '2' occurring with an equal frequency.

The mean is 1.5 and the median is the arithmetic mean of 1 and 2, which is also 1.5
 
Somehow the two 1s and 2s merged and formed a sigle 1 and 2 for me.
Gotta get my eyes checked.
Thanks for the clarification Curious.
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
Replies
1
Views
2K
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 32 ·
2
Replies
32
Views
4K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 0 ·
Replies
0
Views
3K
Replies
14
Views
2K
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K