Modeling a spark gap--How to solve a DE with a step function

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The discussion centers on modeling a spark gap in a Tesla coil circuit, specifically addressing the challenges of solving differential equations with a step function. The user contemplates using Laplace transforms but finds it problematic due to the variable dependency. They clarify that the spark gap is treated as a capacitor, which discharges once a specific voltage is reached. The circuit exhibits two distinct time constants: one slow, linked to the high-voltage capacitor's charge, and one fast, associated with its discharge. Alternative modeling approaches, such as treating the spark gap as a non-linear resistance, are suggested for simplification.
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Homework Statement
I wish to solve a system of differential equations; however, I am modeling a spark gap by using a step function. How could I solve? I'll provide the first equation below as an example:
Relevant Equations
##V_ocos(\omega*t)=\dot Q_1R_1+(Q_2/C_1)(1-U(Q_2-C_1V_o))##
Honestly not sure how to go about this. Again this is one equation of 4 that I have. I considered using Laplace transforms but taking the Laplace transform of a step function whose argument is one of the variables being solved for doesn't seem possible. Also, if there is an alternative way to model a spark gap in a circuit, I would love to be informed of it. Thanks in advance!

(also ##Q_1## and ##Q_2## are the functions of time I wish to solve for)
 
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Could you post the circuit you're trying to model? The RHS suggests a resistor in series with a capacitor "switched" by the spark-gap. Is that O.K?
 
Gordianus said:
Could you post the circuit you're trying to model? The RHS suggests a resistor in series with a capacitor "switched" by the spark-gap. Is that O.K?
I am modeling the basic Tesla coil circuit. In particular, it is this one:
1597265315096.png

The resistor isn't shown in this diagram, however. I am treating the spark gap as a capacitor, whose voltage drops to zero once the voltage across it reaches ##V_o##. I actually entered the first equation wrong--its fixed now.
 
Quite a tricky circuit. It has, at least, two widely different time constants. A slow one, related to the charge of the HV capacitor at mains frequency and a fast one, related to the discharge of the HV capacitor on the primary of the HV transformer. In a simple model I'd consider the spark gap as a non-linear resistance instead of a capacitor.
 

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