Molar Specific Heat of a Gas in Terms of R & s

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SUMMARY

The discussion focuses on calculating the molar specific heat, C_v, of a gas using the equipartition theorem, which states that each degree of freedom contributes an average energy of 1/2 k_B*T. The molar specific heat can be expressed as C_v = (s/2)R, where s represents the degrees of freedom and R is the universal gas constant. Additionally, the discussion highlights that for cis-2-butene (C4H8), with a known C_v of 70.6 J/(mol·K), the number of energetically accessible degrees of freedom can be determined.

PREREQUISITES
  • Understanding of the equipartition theorem
  • Familiarity with molar specific heat concepts
  • Knowledge of thermodynamic principles
  • Basic understanding of kinetic theory of gases
NEXT STEPS
  • Calculate molar specific heat for various gases using the equipartition theorem
  • Explore the relationship between degrees of freedom and molecular structure
  • Investigate the specific heat capacities of different hydrocarbons
  • Learn about the implications of the equipartition theorem in statistical mechanics
USEFUL FOR

Chemists, physicists, and students studying thermodynamics or kinetic theory, particularly those interested in the thermal properties of gases and molecular behavior.

doggieslover
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Part A
Using the equipartition theorem, determine the molar specific heat, C_v, of a gas in which each molecule has s degrees of freedom.
Express your answer in terms of R and s.

Okay, I know that the equipartition theorem is 1/2k_B*T

and molar specific heat is C_v= (1/n)(dU/dT)

But I don't know where to go from here, please help?

Part B

Given the molar specific heat C_v of a gas at constant volume, you can determine the number of degrees of freedom s that are energetically accessible.

For example, at room temperature cis-2-butene, \rm C_4 H_8, has molar specific heat C_v=70.6\;{\rm \frac{J}{mol \cdot K}}. How many degrees of freedom of cis-2-butene are energetically accessible?
Express your answer numerically to the nearest integer.
 
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doggieslover said:
But I don't know where to go from here, please help?
A monatomic molecule has three (translational) degrees of freedom and molar specific heat ##C_V=\frac{3}{2}k_BT.## Does this help?
 
doggieslover said:
Okay, I know that the equipartition theorem is 1/2k_B*T
Your confusion arises because ##\frac 12 k_{\rm B}T## isn't the equipartition theorem. Theorems are generally statements whereas ##\frac 12 k_{\rm B}T## by itself is akin to a single word.

The principle of equipartition of energy states that each degree of freedom has, on average, an associated energy per molecule of ##\frac 12 k_{\rm B}T##.
 

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