- #1

PhysicsFriend

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2. Relevant equations

Q = C_p*n*(delta T)

P(Delta V) = nR(Delta T)

3. Attempt at solution

25 J = C_p (1 mole) (Delta T)

Delta T = .64632 Kelvin

Delta T = -272.35 Celsius

25 J = C_p (1 mole) ( .272.35 Celsius)

C_p = -.0918 J / (mole*Celsius)

4. Question:

I inputted the answer into the online system as +.0918 J / (mole*celsius)

However, it is telling me that I am wrong.

Could there be a negative molar specific heat capacity? That doesn't make too much sense to me because shouldn't the molar specific heat raise the temperature?

Or did I do some stupid mistake with units/wrong equations?