Molecular, total, and net ionic equations for four precipitation and acid-base reactions

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Write the correct chem formula, predict products, and write the molecular, total, and net ionic equations.


1) barium chlorate + lithium carbonate
Ba(ClO3)2 (s) + Li2CO3 (aq) --> BaCO3 (s) + 2LiClO3 (aq)
Ba(ClO3)2 (s) + 2Li(+) + CO3 (2-) --> BaCO3 + 2Li(+) + 2ClO3-
Ba(ClO3)2 (s) + CO3 (2-) (aq) --> BaCO3 (s) + 2ClO3-(aq) ?


2) sodium hydroxide + aluminum SULFATE
6NaOH (aq) + Al2(SO4)2 (aq) --> 3NaSO4 (aq) + 2Al(OH)2 (s)
6Na(+) + 6OH- + 2Al (3+) + 3SO4 (2-) --> 6Na+ + 3SO4 (2-) + 2Al(OH)3 (s)
6OH- (aq) + 2Al (3+) (aq) --> 2Al(OH)3 (s) ?

3) sodium carbonate + hydroiodic acid
Na2CO3 (aq) + 2HI (aq) --> 2NaI (aq) + H2CO3 (s)
2Na (+) + CO3 (2-) + 2H+ + 2I- --> 2Na(+) + H2CO3 (s)
CO3 (2-) (aq) + 2H+ (aq) --> H2CO3 (s) ?


4) barium hydroxide + hydrobromic acid
Ba(OH)2 (aq) + 2HBr (aq) --> Ba(Br)2 (aq) + 2H2O (l)
Ba (2+) + 2OH- + 2H+ + 2Br- --> Ba (2+) + 2Br- + H2O
2OH- (aq) + 2H+ (aq) --> 2H2O (l)?
Thanks.
 
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#1 is fine
#2 you are showing the reaction between aluminum sulfate and sodium hydroxide; not aluminum bromide

Al2SO4 is the wrong formula for aluminum sulfate.

#3 carbonic acid is unstable and breaks up into CO2 and H2O (H2CO3 --> H2O + CO2)

#4 looks good, but Ba(Br)2 should be written as BaBr2 and you can divide your net ionic equation by 2 (by the way all acid-base neutralization equations will have the same net ionic equation of OH- + H+ --> H2O
 
3) CO3 (2-) (aq) + 2H+ (aq) --> H2O (l) + CO2 (g)
2) mistyped question (which explains why I missed Al2(SO4)3 --I'm sorry!)
sodium hydroxide + aluminum sulfate
6OH- (aq) + 2Al (3+) (aq) --> 2Al(OH)3 (s) ?
 
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Can someone check to see if I wrote the equations correctly?


A. magnesium metal + sulfuric acid

Mg (s) + H2SO4 (aq) --> MgSO4 (aq) + H2 (g)
Mg (s) + 2H+ (aq) + SO4 (2-) (aq) --> Mg (2+) (aq) + H2 (g)
Mg(s) + 2H+ (aq) --> Mg (2+) (aq) + H2 (g)

B. lead (II) nitrate + hydrochloric acid

Pb(NO3)2 (aq) + 2HCl (aq) --> PbCl2 (s) + 2HNO3 (aq)
Pb (2+) (aq) + 2NO3- (aq) + 2H+ (aq) + 2Cl- (aq) --> PbCl2 (s) + 2H+ (aq) + 2NO3 - (aq)
Pb (2+) (aq) + 2Cl- (aq) --> PbCl2 (s)

Thanks again.
 
Your correction to the aluminum sulfate looks fine.

A) "Mg (s) + 2H+ (aq) + SO4 (2-) (aq) --> Mg (2+) (aq) + H2 (g)"
Forgot sulfate ion on right side but net ionic is fine.

B) Looks good.