Moles of LiH & LiAlH4: Calculations and Solutions

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Discussion Overview

The discussion revolves around the stoichiometry of the reaction between lithium hydride (LiH) and aluminum to form lithium aluminum hydride (LiAlH4). Participants are exploring how many moles of LiH are needed to produce a specific amount of LiAlH4, as well as clarifying the chemical equation involved in the reaction.

Discussion Character

  • Homework-related
  • Technical explanation

Main Points Raised

  • One participant asks how many moles of LiH are required to make 1 mole of LiAlH4 and how many moles of LiAlH4 can be produced from 6 moles of LiH.
  • Another participant suggests starting by balancing the chemical equation for the reaction.
  • A different participant notes a perceived 4 to 1 ratio between LiH and LiAlH4, proposing that 1.5 moles of LiH would be needed for 1 mole of LiAlH4, but expresses confusion regarding the complete chemical equation.
  • One participant identifies that the missing component in the equation is aluminum chloride (AlCl3), which is necessary for the reaction.

Areas of Agreement / Disagreement

Participants have not reached a consensus on the exact stoichiometric relationships or the complete balanced equation, as there are differing interpretations and some confusion remains regarding the reaction components.

Contextual Notes

The discussion includes assumptions about the stoichiometry that may depend on the specific reaction conditions or definitions of the reactants involved. The exact balancing of the chemical equation has not been fully resolved.

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Homework Statement





*How many moles of LiH are required to make 1 mole of LiAlH4?


* 6 moles of LiH will produce how many moles of LiAlH4?


Can someone help me get started on these?
 
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You start by writing the balancing the relevant equation. Can you do that for the above reaction?
 
I am learning the same stuff in class, I can clearly see from what is written that there is a 4 to 1 ratio, so I think we get 1.5 moles. What I don't see is how the equation works. I wrote it out and somethings seems missing.
LiH + Alxx ----> LiAlH4 + xx
I got myself a bit confused, should there be something for xx or is it just Al?

P.S. I would not normally encroach on someone elses question, but since two weeks have passed, I figured it would be ok.
 
Last edited:
Good thinking. Alxx is actually [itex]AlCl_3[/itex].
 

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