Moment of Inertia and Angular Speed

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SUMMARY

The discussion focuses on calculating the angular speed of a top with a moment of inertia of 4.40 x 10-4 kgm2 after 80.0 cm of string is unwound under a constant tension of 5.19 N. The key concept is the work done by the string, which translates into a change in kinetic energy. Using the equation ΔK = 0.5I(ωfinal2 - ωinitial2), participants derive the final angular velocity based on the work-energy principle.

PREREQUISITES
  • Understanding of moment of inertia and its significance in rotational dynamics.
  • Familiarity with the work-energy theorem in physics.
  • Knowledge of angular velocity and its relationship with rotational motion.
  • Basic algebra for manipulating equations involving kinetic energy.
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  • Study the work-energy theorem in rotational motion.
  • Learn how to calculate angular momentum and its conservation.
  • Explore the relationship between torque, angular acceleration, and moment of inertia.
  • Investigate practical applications of rotational dynamics in engineering contexts.
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TrippingBilly
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A top has a moment of inertia of 4.40 10-4 kgm2 and is initially at rest. It is free to rotate about the stationary axis AA'. A string, wrapped around a peg along the axis of the top, is pulled in such a manner as to maintain a constant tension of 5.19 N. If the string does not slip while it is unwound from the peg, what is the angular speed of the top after 80.0 cm of string has been pulled off the peg? (The picture of the top shows it rotating clockwise about a vertical axis A)

This question has me stumped. If someone could point me in the right direction with regards to a concept I need to know or something I would appreciate it.
 
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Hint: How much work is done by the string?
 
At first I didn't see where you were going, but then I realized that work = change in energy. Which enabled me to use that wonderful equation
delta K = .5I(final angular velocity^2 - initial angular velocity^2). Thanks for the hint!
 

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