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Moment of inertia - disk - finding dm

  • Thread starter O011235813
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  • #1
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Homework Statement





Homework Equations





The Attempt at a Solution




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hey, I am trying to figure out the moment of inertia with respect to various axis. I am, having trouble figuring out how to find out dm.
I know that dm = (rho)*t*dA, but i am having trouble figuring out the t*dA part. i tried using

t*dA = (pi)(r^2)/2
That didn't work. If some1 could help me figure this out i'd be much grateful.

Here is the picture of the disk

[URL=http://img165.imageshack.us/my.php?image=semidiskad3.png][PLAIN]http://img165.imageshack.us/img165/6294/semidiskad3.png[/URL] http://g.imageshack.us/img165/semidiskad3.png/1/ [Broken][/PLAIN]

Homework Statement





Homework Equations





The Attempt at a Solution

 
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Answers and Replies

  • #2
tiny-tim
Science Advisor
Homework Helper
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Hi O011235813! :smile:
hey, I am trying to figure out the moment of inertia with respect to various axis. I am, having trouble figuring out how to find out dm.
I know that dm = (rho)*t*dA, but i am having trouble figuring out the t*dA part. i tried using

t*dA = (pi)(r^2)/2
That didn't work. If some1 could help me figure this out i'd be much grateful.
hmm … no replies in almost 24 hours …

so I'm guessing everyone's as confused as I am :confused:

dm is an element of mass, and rho is density, but what are t and dA supposed to be, what shape volume are you considering (the diagram doesn't make it clear), about which axis, and how are you trying to "slice up" this volume for integration?
 
  • #3
11
0
hey,

yeah sorry for the confusing. I figured it out so i'm good now. Thanks for replying back though :D
 

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