The flywheel of a gasoline engine is required to give up 500 J of kinetic energy while its angular velocity decreases from 650 rev/min to 520 rev/min. What moment of inertia is required?
K = (1/2) * I * w^2
K = kinetic energy
I = moment of inertia
w = angular velocity
The Attempt at a Solution
I thought that since the engine gives up 500 J of KE (so change of 500?) I can plug in 500 for K, and the final angular velocity for w, to solve for I.
500 = (1/2) * I * ((520)/60) * 2pi)^2
I = .337 kg m^2
The correct answer is 0.600 kg m^2. What am I doing wrong here? thanks