A thin uniform rod of mass (M) and length (L) is bent at its center so that the two segments are now perpendicular to each other.
a. Find its moment of inertia about an axis perpendicular to its plane and passing through the point where the two segments meet.
I = (integral) r^2 dm
I have a picture drawn (attached) but don't know how to proceed from here.
Thank you for any help
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