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Moment of Inertia of a Rectangular Picture Frame

  • Thread starter kepherax
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Homework Statement
A picture frame consists of 4 thin pieces of wood glued together. Each wooden piece has the same mass per unit length lambda. The dimensions of each piece is given below. Determine the rotational inertia of the frame about the dashed axis.
Homework Equations
I = mr^2, for rod at edge I = 1/3 mr^2
I total = I1+I2+I3....+In
View attachment 250905

I know the answer, but am not certain how they got Lsin(angle) for R?
 
Last edited:

haruspex

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Homework Statement: A picture frame consists of 4 thin pieces of wood glued together. Each wooden piece has the same mass per unit length lambda. The dimensions of each piece is given below. Determine the rotational inertia of the frame about the dashed axis.
Homework Equations: I = mr^2, for rod at edge I = 1/3 mr^2
I total = I1+I2+I3....+In

View attachment 250905

I know the answer, but am not certain how they got Lsin(angle) for R?
The link does not work for me. Please post an attempt, per forum rules.
 
7
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I don't know why it won't let me edit this, but here is the problem and my attempt.

frame.JPG


20191010_082036.jpg
 

haruspex

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how they got Lsin(angle) for R?
Consider a small element dx of one of the spars length L, distance x from the end at the axis.
Its distance from the axis is ##x\sin(\theta)##, so its MoI about the axis is ##\lambda dx (x\sin(\theta))^2##. Then integrate, or observe that this is the same as if the spar were the same mass but length ##L\sin(\theta)## and normal to the axis.
 

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