Moment of Inertia question (dead simple)

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Homework Help Overview

The discussion revolves around calculating the moment of inertia for a thin disk with given mass, diameter, and thickness, focusing on the rotation about the central axis.

Discussion Character

  • Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to calculate the moment of inertia using the formula I=(1/2)MR², questioning the relevance of thickness in the calculation. Another participant provides the multiple choice options for the answer, while one participant expresses agreement with the calculated value.

Discussion Status

The discussion is ongoing, with participants exploring the calculation and questioning the provided answer choices. There is some agreement on the calculated value, but the context of the multiple choice options remains unclear.

Contextual Notes

Participants note that the answer found by the original poster does not match any of the provided multiple choice options, raising questions about the validity of the calculation or the options themselves.

heyall
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Homework Statement


A thin disk is 100g.
It's diameter is 20cm.
It's thickness is 2cm.

Rotation is about the central axis (ie. perpendicular to the symmetrical plane).
Answer in kg*m2

Homework Equations



I=(1/2)MR2
M is the mass
R is the radius
I is the moment of inertia

The Attempt at a Solution



R = half the diameter ∴ R = 10cm

I= (.5)(.1)(.1)2
I= 0.0005 = 5*10^-4


I don't think the thickness matters as long as it is symmetrical all around.

The reason I ask is because this question is a multiple choice question for marks, but the answer I found (0.0005) wasn't listed as one of the options. Thanks!
 
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heyall said:

Homework Statement


A thin disk is 100g.
It's diameter is 20cm.
It's thickness is 2cm.

Rotation is about the central axis (ie. perpendicular to the symmetrical plane).
Answer in kg*m2

Homework Equations



I=(1/2)MR2
M is the mass
R is the radius
I is the moment of inertia

The Attempt at a Solution



R = half the diameter ∴ R = 10cm

I= (.5)(.1)(.1)2
I= 0.0005 = 5*10^-4

I don't think the thickness matters as long as it is symmetrical all around.

The reason I ask is because this question is a multiple choice question for marks, but the answer I found (0.0005) wasn't listed as one of the options. Thanks!
What are the possible options?
 
5E-6
1E-7
5E5
2E-5
1E4

Where the letter E indicates scientific notation.
 
heyall said:
5E-6
1E-7
5E5
2E-5
1E4

Where the letter E indicates scientific notation.

I agree, it's 5E-4.
 

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