Moments & Pivots: Find Force T for Level Board

  • Thread starter Thread starter Sarahborg
  • Start date Start date
  • Tags Tags
    Moments
Click For Summary
SUMMARY

The discussion focuses on calculating the upward vertical force T required to keep a uniform board of length 90 cm and weight 6 N level when pivoted at one end. The correct approach involves using the moment equation, where the moment is defined as Moment = Force x Perpendicular distance. The calculated force T is confirmed to be 3 N, as the moment balance equation (-45 cm * 6 N + 90 cm * 3 N) equals zero, indicating no angular acceleration.

PREREQUISITES
  • Understanding of moments and torque in physics
  • Familiarity with Newton's laws of motion
  • Basic knowledge of angular motion concepts
  • Ability to perform calculations involving force and distance
NEXT STEPS
  • Study the relationship between linear and angular motion
  • Learn about calculating torque and its applications in physics
  • Explore the concept of moment of inertia and its significance
  • Investigate Newton's laws as they apply to rotational dynamics
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and rotational dynamics, as well as educators seeking to clarify concepts related to moments and forces.

Sarahborg
Messages
19
Reaction score
1

Homework Statement


A uniform board of length 90cm is pivoted at a hinge at one end. It is kept level by an upward vertical force T applied at the opposite end. The weight of the board is 6N. Take moments about the hinge to find T when the board is level.

Homework Equations


Moment = Force x Perpendicular distance

The Attempt at a Solution


I tried doing 45 x 6 = 270, and then 270/90 which is 3N. I think it's wrong though (I got the 45 by dividing 90 by 2)
 
Physics news on Phys.org
Hello Sarah, :welcome:

Much better !
What makes you doubt the result ?
Your moment balance looks like ( -45 * 6 + 90 * 3) cm * N and that is zero, so no angular acceleration.
 
  • Like
Likes   Reactions: Sarahborg
+1

Welcome to the forum. It looks right to me as well.
 
  • Like
Likes   Reactions: Sarahborg
CWatters said:
+1

Welcome to the forum. It looks right to me as well.
Thank you very much
 
How do you calculate angular acceleration, because we haven't covered it yet, and got curious.

Thank you very much for your help :)
 
Pardon the link: :smile: there is a parallel between linear motion and angular motion.
 
  • Like
Likes   Reactions: Sarahborg and CWatters
Although in this case there is no angular acceleration because you were asked to arrange for the net torque to sum to zero. See also Newton's laws.
 
  • Like
Likes   Reactions: Sarahborg
BvU said:
Pardon the link: :smile: there is a parallel between linear motion and angular motion.
Thanks
 
How are Newton's Laws related to angular acceleration?

Thanks
 
  • #10
Have you come to the conclusion the answer you found in post #1 is correct ? Oh well, I hinted as much in post #2.

For Newton we have $$ \vec F = m\vec a $$ and the (almost carbon copy)https://www.boundless.com/physics/textbooks/boundless-physics-textbook/uniform-circular-motion-and-gravitation-5/angular-vs-linear-quantities-59/angular-vs-linear-quantities-272-6253/in angular motion is $$ \vec \tau = I\vec \alpha $$
(see table 1 https://www.boundless.com/physics/textbooks/boundless-physics-textbook/rotational-kinematics-angular-momentum-and-energy-9/problem-solving-88/problem-solving-techniques-332-6291/)
## \vec \tau ## is the torque
## I ## is the moment of inertia
##\vec \alpha## is the angular acceleration
 
  • Like
Likes   Reactions: Sarahborg and CWatters

Similar threads

Replies
6
Views
2K
Replies
4
Views
3K
Replies
17
Views
3K
Replies
1
Views
6K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 15 ·
Replies
15
Views
4K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 7 ·
Replies
7
Views
3K
Replies
3
Views
2K
  • · Replies 8 ·
Replies
8
Views
4K