- #1

vinci

- 12

- 4

## Homework Statement

A metal rod of length 90cm has a disc of radius 24cm fixed rigidly at its centre(refer to picture attached). The assembly is pivoted at it's centre.

Two forces, each of magnitude 30N, are applied normal to the rod at each end so as to produce a turning effect on rod. A rope is attached to the edge of the disc to prevent rotation

1-Calculate the torque of couple produced by the 30N forces

2-the tension T in the rope

## Homework Equations

Torque= moment arm * force applied perpendicular to pivot

torque of couple=distance between two forces * one of the force

(I assume the above equations will be relevant)

## The Attempt at a Solution

For the rod the torque of couple would be

30 * 90 =2700

Now since the rotation is to be prevented by the disc in center it has to produce an equal torque in the opposite direction(anti-clockwise direction) so the torque produced by disc should also be 2700

and since

torque=moment arm*force applied

=radius*tension in string

2700= 24 * T

T=2700/24Have I solved the above numerical correctly? Since the book doesn't provide answer to these questions and I have no tutor I have no other way to confirm my calculations.