Momentsand Forces acting on a ruler

  • Thread starter Thread starter sarahcate
  • Start date Start date
  • Tags Tags
    Forces
Click For Summary
SUMMARY

The discussion focuses on the calculation of moments and forces acting on a meter ruler, specifically when it is pivoted and supported by a Newton meter. The ruler, weighing 1.0N, is pivoted at the 10cm mark, with a 3.0N weight suspended at the 30cm mark. The calculated force T required to keep the ruler horizontal is 1.25N. When the Newton meter is raised, the force must increase due to the introduction of a horizontal component, despite the vertical component remaining unchanged.

PREREQUISITES
  • Understanding of the principle of moments
  • Knowledge of forces and their components
  • Familiarity with basic physics concepts related to equilibrium
  • Ability to perform calculations involving torque
NEXT STEPS
  • Study the principle of moments in detail
  • Learn about torque and its applications in static equilibrium
  • Explore vector components of forces in physics
  • Investigate the effects of angles on force magnitudes in equilibrium scenarios
USEFUL FOR

Students studying physics, educators teaching mechanics, and anyone interested in understanding the principles of moments and forces in static systems.

sarahcate
Messages
5
Reaction score
0
I have a question about moments a forces acting on a meter ruler.

"A meter ruler of weight 1.0N is pivoted on a nail passing through a hole drilled at the 10cm mark. A weight of 3.0N is suspended at the 30cm mark. A Newton meter supports the ruler at the 90cm mark so that it is horizontal.
a) use the principle of moments to calculate the magnitude of force T needed to keep the ruler horizontal.
b)the Newton meter is raised until the rule makes an angle A with the horizontal. Without doing any further calculations copare the magnitude of the force provided by the Newton meter in this new positionwith the force T when the rule was horizontal. Explain your answer."

For part a I had (0.2 x 3) + (0.4 x 1) = 0.8T
to give T = 1.25N

For part b I am confused. Intuitively I think the force should have increased but I'm not really sure why and since none of the distances have changed and the weights are the same I don't how it can have changed.

Please help!
 
Physics news on Phys.org
Sarahcate said:
I have a question about moments a forces acting on a meter ruler.

"A meter ruler of weight 1.0N is pivoted on a nail passing through a hole drilled at the 10cm mark. A weight of 3.0N is suspended at the 30cm mark. A Newton meter supports the ruler at the 90cm mark so that it is horizontal.
a) use the principle of moments to calculate the magnitude of force T needed to keep the ruler horizontal.
b)the Newton meter is raised until the rule makes an angle A with the horizontal. Without doing any further calculations copare the magnitude of the force provided by the Newton meter in this new positionwith the force T when the rule was horizontal. Explain your answer."

For part a I had (0.2 x 3) + (0.4 x 1) = 0.8T
to give T = 1.25N

For part b I am confused. Intuitively I think the force should have increased but I'm not really sure why and since none of the distances have changed and the weights are the same I don't how it can have changed.

Please help!
Since it is still supporting the same weight, the vertical component of force must be the same. Now, the horizontal component is non-zero. what does that tell you about the magnitude of the force?
 
If there is now a horizontal component the force must have increased to include this.

Where does the horizontal component come from?
 

Similar threads

Replies
6
Views
3K
  • · Replies 15 ·
Replies
15
Views
13K
  • · Replies 8 ·
Replies
8
Views
1K
  • · Replies 4 ·
Replies
4
Views
14K
  • · Replies 26 ·
Replies
26
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
1
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K