# Momentum and Collisions in 2 dimensions

## Homework Statement

Two particles with masses 2m and 3m are moving toward each other along the x axis with the same initial speeds v. Particle 2m is traveling to the left, while particle 3m is traveling to the right. They undergo an elastic, glancing collision such that particle 2m is moving downward after the collision at a right angle from its initial direction.

## Homework Equations

v2 = final velocity of the 3m object
v3 = final velocity of the 2m object
angle w = the angle of 3m to the horizontal after colliding with the 2m

momentum conserved in x-dimension:
3mv - 2mv = 3m * cos(w) * v2

momentum conversed in y-dimension:
0 = (3m * sin(w) * v2) - (2m * v3)

kinetic energy is also conserved:
.5(3m)(v^2) + .5(2m)(v^2) = .5(3m)(v2^2) + .5(2m)(v3^2)

## The Attempt at a Solution

pages of work of which i am too tired now to transcribe into type

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