Momentum and conservation of momentum

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SUMMARY

The discussion centers on the principles of momentum conservation in a system involving a car with mass M1 and a box with mass M2. When the box is shot vertically with speed v1 relative to the car, the final horizontal speed of the car remains unchanged due to the absence of friction. The conservation of momentum formula, m1 v1 = m2 v2, applies initially, indicating that the car's vertical motion is influenced by the box's vertical speed until the suspension system dampens the effect.

PREREQUISITES
  • Understanding of classical mechanics principles, specifically momentum conservation.
  • Familiarity with mass, velocity, and their relationship in physics.
  • Knowledge of frictionless systems and their implications on motion.
  • Basic comprehension of suspension systems in vehicles.
NEXT STEPS
  • Study the conservation of momentum in two-dimensional collisions.
  • Explore the effects of friction on momentum conservation in real-world scenarios.
  • Learn about the dynamics of suspension systems and their role in vehicle motion.
  • Investigate the mathematical modeling of motion in frictionless environments.
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Physics students, automotive engineers, and anyone interested in the dynamics of motion and momentum conservation in mechanical systems.

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A car with mass M1,with a box upon it of mass M2 moves with constant speed v.(there is no friction).If the box is shot vertically with speed v1 relative to the car then the final speed of the car will remain orizontial?or it will be floating downwards in relation to an observer that is at rest?
 
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Without suspension it would be the car plus the Earth which move 'downwards' with a vanishingly small vertical velocity.
With suspension, the vertical speed of the car would be, initually, according to the momentum conservation formula,
m1 v1 = m2v2
until the springs slowed it down etc..
 

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