Conservation of momentum and energy problem

In summary: Therefore, solution 2 where the "following" car has the faster speed is not physically possible. In summary, in an elastic collision between two identical bumper cars, with the initial speed of the leading car being 5.60 m/s and the following car being 6.00 m/s, the final speeds of the cars can either be v=5.6 m/s and w=6.0 m/s or v=6.0 m/s and w=5.6 m/s. However, the second solution is not physically possible as the following car cannot have a faster speed than the leading car.
  • #1
photon184739
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In an elastic collision, a 400-kg bumper car collides directly from behind with a second, identical bumper car that is traveling in the same direction. The initial speed of the leading bumper car is 5.60 m/s and that of the trailing car is 6.00 m/s. Assuming that the mass of the drivers is much, much less than that of the bumper cars, what are their final speeds?

Name "v" the unknown final speed of the 'leading' bumper care and "w" to the unknown final speed of the 'following' bumper car.

400kg*5.60 m/s + 400kg*6.00 m/s = 400kg*v + 400kg*w (conservation of momentum)
1/2*(400kg)*(5.60 m/s)^2 +1/2*(400kg)*(6.00 m/s)^2 = 1/2*400kg*v^2 + 1/2*400kg*w^2 (conservation of energy)

5.60 m/s + 6.00 m/s = v + w
5.60 m/s + 6.00 m/s = v^2 + w^2

The above system of 2 equations has the following 2 solutions:

https://www.wolframalpha.com/input/?i=5.6+6.0=v+++w,+5.6^2+++6.0^2+=+v^2+++w^2

solution 1: v=5.6, w=6.0
solution 2: v=6.0, w=5.6

Why are there 2 solutions? What additional constraint is needed to know that the leading bumper car's final speed v = 6.0 and the following bumper car's speed w = 5.6?
 
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  • #2
All the maths does is find values of ##v## and ##w## so that the total momentum and energy are equal to their initial values. Do you notice anything about one solution for ##v## and ##w## compared to the initial values of velocity?
 
  • #3
photon184739 said:
Summary:: conservation of momentum and energy problem

Why are there 2 solutions?
Both energy and momentum are conserved either if they collide elastically or if they miss and don’t collide at all.
 
  • #4
In addition to any other responses you get, if you need Wolfram Alpha to solve two equations in two unknowns, you need to up your algebra game if you want to succeed in physics. (There's also at least one more mistake)
 
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  • #5
Vanadium 50 said:
(There's also at least one more mistake)
Indeed, although it appears to be a typo since the equations as written have complex roots. @photon184739, maths is a lot easier to understand on forums if you use LaTeX, and hence you are less likely to make typos. Check out the guide linked below the reply box.
 
  • #6
photon184739 said:
Summary:: conservation of momentum and energy problem

Why are there 2 solutions? What additional constraint is needed to know that the leading bumper car's final speed v = 6.0 and the following bumper car's speed w = 5.6?
The additional constraint is imposed by common sense. As long as there has been a collision, the following car can only be "following" if it is moving slower than the "leading" car.
 

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