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photon184739
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In an elastic collision, a 400-kg bumper car collides directly from behind with a second, identical bumper car that is traveling in the same direction. The initial speed of the leading bumper car is 5.60 m/s and that of the trailing car is 6.00 m/s. Assuming that the mass of the drivers is much, much less than that of the bumper cars, what are their final speeds?
Name "v" the unknown final speed of the 'leading' bumper care and "w" to the unknown final speed of the 'following' bumper car.
400kg*5.60 m/s + 400kg*6.00 m/s = 400kg*v + 400kg*w (conservation of momentum)
1/2*(400kg)*(5.60 m/s)^2 +1/2*(400kg)*(6.00 m/s)^2 = 1/2*400kg*v^2 + 1/2*400kg*w^2 (conservation of energy)
5.60 m/s + 6.00 m/s = v + w
5.60 m/s + 6.00 m/s = v^2 + w^2
The above system of 2 equations has the following 2 solutions:
https://www.wolframalpha.com/input/?i=5.6+6.0=v+++w,+5.6^2+++6.0^2+=+v^2+++w^2
solution 1: v=5.6, w=6.0
solution 2: v=6.0, w=5.6
Why are there 2 solutions? What additional constraint is needed to know that the leading bumper car's final speed v = 6.0 and the following bumper car's speed w = 5.6?
Name "v" the unknown final speed of the 'leading' bumper care and "w" to the unknown final speed of the 'following' bumper car.
400kg*5.60 m/s + 400kg*6.00 m/s = 400kg*v + 400kg*w (conservation of momentum)
1/2*(400kg)*(5.60 m/s)^2 +1/2*(400kg)*(6.00 m/s)^2 = 1/2*400kg*v^2 + 1/2*400kg*w^2 (conservation of energy)
5.60 m/s + 6.00 m/s = v + w
5.60 m/s + 6.00 m/s = v^2 + w^2
The above system of 2 equations has the following 2 solutions:
https://www.wolframalpha.com/input/?i=5.6+6.0=v+++w,+5.6^2+++6.0^2+=+v^2+++w^2
solution 1: v=5.6, w=6.0
solution 2: v=6.0, w=5.6
Why are there 2 solutions? What additional constraint is needed to know that the leading bumper car's final speed v = 6.0 and the following bumper car's speed w = 5.6?