Momentum and movement basic GCSE Quest

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SUMMARY

The discussion revolves around a physics problem involving momentum conservation when Mr. Green, with a mass of 80 kg, steps off a boat weighing 35 kg at a speed of 3 m/s. The total momentum before and after Mr. Green steps off must remain zero. The correct calculation for the boat's velocity is derived from the equation: momentum of Mr. Green (240 kg m/s) equals the negative momentum of the boat, leading to a boat velocity of approximately -6.86 m/s. The participants clarify the importance of using vector signs in momentum calculations.

PREREQUISITES
  • Understanding of momentum conservation principles
  • Familiarity with basic physics formulas, including momentum (p = mv)
  • Knowledge of vector quantities and their significance in physics
  • Ability to perform algebraic manipulations for solving equations
NEXT STEPS
  • Study the concept of momentum conservation in closed systems
  • Learn how to apply vector notation in physics problems
  • Explore real-world applications of momentum in collisions
  • Review examples of momentum calculations involving multiple objects
USEFUL FOR

Students preparing for GCSE physics, educators teaching momentum concepts, and anyone interested in understanding the principles of motion and forces in physics.

nonthesecond
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Mr Green, mass 80 kg, stepped off a boat of mass 35 kg at a speed of 3m/s. how fast did the boat move in the opposite direction?

i have no idea how to work it out?
 
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nonthesecond said:
Mr Green, mass 80 kg, stepped off a boat of mass 35 kg at a speed of 3m/s. how fast did the boat move in the opposite direction?

i have no idea how to work it out?

I think you will find that Mr Green and the boat are assumed to be at rest initially, so the total momentum was - and will remain - zero.
 
PeterO said:
I think you will find that Mr Green and the boat are assumed to be at rest initially, so the total momentum was - and will remain - zero.

ok thanks but how do i answer the question?
 
PeterO said:
I think you will find that Mr Green and the boat are assumed to be at rest initially, so the total momentum was - and will remain - zero.

i still don't understand i don't understand what formula to use as well.
 
nonthesecond said:
i still don't understand i don't understand what formula to use as well.

If you define the direction Mr Green goes as positive, he will have some positive momentum after he leaves the boat.
To maintain a total of zero, the boat must have an equal sized, but negative momentum - so it will be traveling at an appropriate speed in the negative direction (ie the other way)
 
PeterO said:
If you define the direction Mr Green goes as positive, he will have some positive momentum after he leaves the boat.
To maintain a total of zero, the boat must have an equal sized, but negative momentum - so it will be traveling at an appropriate speed in the negative direction (ie the other way)

i think i remeber my teacher saying that it's: 80 + 35= 115
115 x 3 = 375
375/35 = 1.3...m/s

is that correct?
 
nonthesecond said:
i think i remeber my teacher saying that it's: 80 + 35= 115
115 x 3 = 375
375/35 = 1.3...m/s

is that correct?

Sadly, no.

When you added the masses and multiplied by 3 (presumably the speed of Mr Green), you calculate the momentum if both he and the boat were traveling at that veocity; only he is.
 
nonthesecond said:
i think i remeber my teacher saying that it's: 80 + 35= 115
115 x 3 = 375
375/35 = 1.3...m/s

is that correct?

answer these in order:
What is Mr Green's mass?

What is Mr Green's velocity?

What is Mr Green's momentum?

What is the boat's momentum?

What is the boat's mass?

What is the boat's velocity?
 
PeterO said:
answer these in order:
What is Mr Green's mass?

What is Mr Green's velocity?

What is Mr Green's momentum?

What is the boat's momentum?

What is the boat's mass?

What is the boat's velocity?

you are very kind for helping me.

80kg

240 kg m/s

105 kg m/s

35kg

no idea for velocity i know formula is f=d/t but you aren't given time or distance.
 
  • #10
nonthesecond said:
you are very kind for helping me.

80kg correct

(+3) - but you didn't answer that question

+240 kg m/s almost correct

105 kg m/s incorrect

35kg correct

no idea for velocity i know formula is f=d/t but you aren't given time or distance.

For that final velocity - think about how you calculated the momentum of Mr Green - and don't forget to use + and - signs correctly.
Velocity is a vector; so can be positive or negative.

EDIT: Hint - answers 3 and 4 add up to zero
 
  • #11
PeterO said:
For that final velocity - think about how you calculated the momentum of Mr Green - and don't forget to use + and - signs correctly.
Velocity is a vector; so can be positive or negative.

EDIT: Hint - answers 3 and 4 add up to zero

is the answer 240/35?
 
  • #12
PeterO said:
For that final velocity - think about how you calculated the momentum of Mr Green - and don't forget to use + and - signs correctly.
Velocity is a vector; so can be positive or negative.

EDIT: Hint - answers 3 and 4 add up to zero

did i get the question right?
 
  • #13
nonthesecond said:
is the answer 240/35?

Certainly is.
 

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